A rectangle has height and width changing in such a way that the area remains constant 2 square feet. At the instant the height
1 answer:
Answer:
ft/min indicates the rate at which the width changes.
Step-by-step explanation:
Provided -
The area always maintains a consistent value of 2 square feet.
Height of the rectangle = 2 feet
Rate of height change = 6 feet per minute
Since the area is consistent
2 sq ft = (2 * 6) ft/min * 1 * x ft/min
x = ft/min
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Answer:
The answer is option (A).
Step-by-step explanation:
Let X represent the count of orange milk chocolate M&M’s.
The proportion of orange milk chocolate M&M’s is defined as p = 0.20.
In a small bag containing milk chocolate M&M’s, n is established at 55.The occurrence of an orange milk chocolate M&M is independent of the remaining candies.The random variable X conforms to a Binomial distribution characterized by parameters n = 55 and p = 0.20.
Calculating the average number of orange milk chocolate M&M’s in a package of 55 candies proceeds as follows:
It is noted that in a randomly selected pack of milk chocolate M&M's there were 14 orange M&M's, indicating that the ratio of orange milk chocolate M&M's in that selection was 25.5%.
This ratio is not unexpected.
This is due to the expected count of orange milk chocolate M&M’s in a 55 candy bag being estimated at 11. Therefore, encountering 14 orange milk chocolate M&M’s does not seem unusual.
Unusual instances typically have exceedingly low probabilities, specifically below 0.05.
To calculate the probability of having P (X ≥ 14), follow the subsequent calculation:
The likelihood of obtaining 14 or more orange candies in a milk chocolate M&M’s bag is 0.1968.
This probability is considerably higher than 0.05.
Thus, the correct answer is option (A).