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Citrus2011
1 month ago
13

A rectangle has height and width changing in such a way that the area remains constant 2 square feet. At the instant the height

is 2 feet, the height is changing at a rate of 6 feet/minute. Find the rate of change of the width (in feet/min) at that instant.
Mathematics
1 answer:
Leona [12.6K]1 month ago
4 0

Answer:

\frac{1}{3} ft/min indicates the rate at which the width changes.

Step-by-step explanation:

Provided -

The area always maintains a consistent value of 2 square feet.

Height of the rectangle = 2 feet

Rate of height change = 6 feet per minute

Since the area is consistent

2 sq ft = (2 * 6) ft/min * 1 * x ft/min

x = \frac{1}{3} ft/min

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It takes 5.22 hours to install carpet in a room. Step-by-step explanation: To start, let's explore the relationship among yards, feet, and inches. 1. 1 yard = 3 feet. 2. 1 foot = 12 inches. 3. Therefore, 1 yard = 36 inches. Now, let's convert all measurements to inches. ∵ 1 yard = 36 inches ∴ 1 yard² = (36)² inches². - Fine Floors can outfit 15 square yards of carpeting in 4 hours and 30 minutes. ∵ 15 yard² equals 15 × (36)² inches², so 15 yards² = 19440 inches². ∵ 1 hour equals 60 minutes, thus 30 minutes = 0.5 hours. Consequently, 4 hours and 30 minutes = 4.5 hours, implying Fine Floors covers 19440 inches² in 4.5 hours. The dimensions of the room are 11 feet 9 inches by 13 feet 4 inches. ∵ 1 foot = 12 inches, therefore, 11 feet 9 inches = 11 × 12 + 9 = 141 inches, and 13 feet 4 inches = 13 × 12 + 4 = 160 inches. Hence, the room’s area is 141 × 160 = 22560 inches². Using the ratio method, we have area of carpeting (in²): time of carpeting (hr) hence, 19440: 4.5 = 22560: h. By cross-multiplying, 19440h = 4.5 × 22560 yields 19440h = 101520. Dividing both sides by 19440 results in h = 5.22 hrs.
8 0
18 days ago
Read 2 more answers
How do I write 56 1/4% as a fraction in simplest form
Svet_ta [12734]
56 1/4% = 9/16
I hope this information is useful!
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1 month ago
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A photographer sells large photos for $27 profit and small photos for an $11 profit.This past year,she sold 126 photos and made
Leona [12618]

Answer:

The photographer sold 72 small photos and 54 large photos.

Step-by-step explanation:

We can create a system of equations based on the details provided. Let X represent small photos and Z represent large photos.

It is given that the total number of photos sold is 126:

X + Z = 126

Additionally, she generated $2,250 from selling specific amounts of small and large photos, stated as:

$2,250 = $11X + $27Z

From the first equation, we know X=126-Z. Substituting this into the second equation gives:

2,250 = 11(126-Z) + 27Z

2,250 = 1,386 - 11Z + 27Z

2,250 - 1,386 = 16Z

864 = 16Z

Z = 864/16

Z = 54, which indicates the number of large photos sold. To find X:

X = 126 - Z

X = 126 - 54

X = 72, representing the small photos sold.

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1 month ago
Two fathers and two sons own 21 horses. They are moving to different parts of the country and want to divide the horses evenly a
tester [12383]
They cannot possess the same number of horses; let me clarify. If you divide 21 horses among four individuals, you would perform 21/4, yielding 5.25, implying that fractional horses are unfeasible. Therefore, at least one individual must have 6 horses instead of 5. Possibly, this is what your instructor wants you to understand. For an even distribution, they could sell one horse, making it 20, so each would then have 5 horses. Alternatively, they might share the extra horse to rotate its usage.
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26 days ago
3.7.6 .WP A state runs a lottery in which six numbers are randomly selected from 40 without replacement. A player chooses six nu
PIT_PIT [12445]

Answer:

a) 2.60x10^-7

b) 5.31x10^-5

c) 2.19x10^-3

Step-by-step explanation:

X=the number of hits

Probability can be determined by taking the number of successful outcomes and dividing it by the total number of possible outcomes.

Now

a) P(X=6)=P({1, 1, 1, 1, 1, 1})=6/40*5/39*4/38*3/37*2/36*1/35=2.60x10^-7

b) P(X=5)=P({0, 1, 1, 1, 1, 1})+P({1, 0, 1, 1, 1, 1})+...+P({1, 1, 1, 1, 1, 0}), and each scenario carries the same probability

P(X=5)=6P({1, 1, 1, 1, 1, 0})=6*(6/40*5/39*4/38*3/37*2/36*34/35)=5.31x10^-5

c) P(X=4)=P({0, 0, 1, 1, 1, 1})+...+P({1, 1, 1, 1, 0, 0}), where each case has an identical probability.

P(X=4)=(^6_4)P({1, 1, 1, 1, 0, 0})=\frac{6!}{4!(6-4)!}(\frac{6}{40} \frac{5}{39} \frac{4}{38} \frac{3}{37} \frac{34}{36} \frac{33}{35} )=2.19\times 10^{-3}

3 0
1 month ago
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