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7nadin3
18 days ago
10

Solve x2 + 12x = –11 by completing the square. Which is the solution set of the equation? {–11, –1} {–11, 1} {11, –1} {11, 1} ,

PLEASE HURRY !! :( THANK YOU!
Mathematics
2 answers:
PIT_PIT [9.1K]18 days ago
3 0
Original Equation:

x^2 + 12x = -11

Rearrange this into standard quadratic form by moving -11 to the other side:

x^2 + 12x + 11 = 0

Determine two numbers that will multiply to 11 and sum to 12, then break it down:

(x + 1)(x + 11) = 0

Solve for x from both equations:

x+1 = 0
x = -1

x + 11 = 0
x = -11

The final solution set is: {-11, -1}
Leona [9.2K]18 days ago
3 0
To solve for the variable, since the coefficient of x^2 is 1,
take half of the linear coefficient (12) and square it
12/2=6, 6^2=36
add this to both sides
x^2+12x+36=-11+36
factor the perfect square
(x+6)^2=25
find the square root of both sides, considering both positive and negative results
x+6=+/-5
subtract 6 from both sides
x=-6+/-5
thus, x can be -1 or -11

the solution is {-11,-1}
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