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KengaRu
1 month ago
10

L = loudness, in decibels (dB); I = sound intensity, in watts/m2; I0 = 10−12 watts/m2

Mathematics
2 answers:
Leona [12.6K]1 month ago
7 0

The intensity of sound from a jackhammer measures 96 dB, equating to a sound intensity of approximately 0.004.

The sound intensity of a compactor reads as 94 dB, with a sound intensity of about 0.0025.

The sound intensity of the jackhammer is roughly 1.6 times that of the compactor.

With pile driver loudness at 112 dB, how many times greater is this sound intensity compared to the jackhammer? Round it to the nearest ten.

40

Leona [12.6K]1 month ago
3 0
The sound intensity produced by the Pile Driver is approximately 39.5
 which is close to 40 times that of a jackhammer.


Given the Loudness in dB for pile driver = 112 dB
we need to convert this into sound intensity.
To begin,
112dB/10 = 11.2 

Now, we utilize this value as the exponent of 10
(10)^(11.2) = 1.5849 * 10 ^ 11

Next, we apply the formula of Watts per square meter to determine the intensity:
I / (10^-12 W/m^2) =1.5849 * 10 ^ 11
I = sound intensity = 0.158

We can then compare:

Sound intensity of Pile Driver/ Sound intensity of Jackhammer
(0.158) / (0.004)
= 39.5
or roughly 40 times the jackhammer.
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