Consider the quadratic function.

1 answer:

4 0

A quadratic function in standard form is expressed as
f(x) = ax² + bx + c
with coefficients a, b, and c.

The quadratic function provided is
f(p) = p² - 8p - 5
By relating this to the standard form, where p stands in for x, we find:
a = 1 because the leading coefficient is 1*p²,
b = -8 as the linear part is -8*p,
and c = -5 since the constant is -5.

Based on the choices available, the correct answer is the third one:
a = 1, b = -8, c = -5.

You might be interested in

Segment GI is congruent to Segment JL and Segment GH is congruent to Segment KL. I have to prove Segment HI is congruent to Segm

Zina [12379]

Solution:

Refer to the detailed explanation

Step-by-step process:

1 step: $\overline{GI}\cong \overline {JL}$ - provided

2 step: $\overline{GI}\cong \overline{GH}+\overline{HI}$ - Segments Addition Postulate

3 step: $\overline{GH}+\overline{HI}\cong \overline {JL}$ - Substitution Property

4 step: $\overline {JL}\cong \overline {JK}+\overline {KL}$ - Segments Addition Postulate

5 step: $\overline{GH}+\overline{HI}\cong \overline {JK}+\overline {KL}$ - Substitution Property

6 step: $\overline{GH}\cong \overline {KL}$ - provided

7 step: $\overline{GH}+\overline{HI}\cong \overline {JK}+\overline {GH}$ - Property of Substitution Equality

8 step: $\overline{HI}\cong \overline {JK}$ - Equality Subtraction Property

3 0

2 months ago

What is the approximate area of the shaded sector in the circle shown below

PIT_PIT [12445]

$\bf \textit{area of a sector of a circle}\\\\
A=\cfrac{\theta \pi r^2}{360}~~
\begin{cases}
r=radius\\
\theta =angle~in\\
\qquad degrees\\
------\\
r=4.5\\
\theta =150
\end{cases}\implies A=\cfrac{(150)(\pi )(4.5)^2}{360}\\\\\\ A=\cfrac{3037.5\pi }{360}$