Answer:
The answer is A. 990.
Step-by-step explanation:
To determine the maximum duration that any of the mowers can run.
The three lawn-service mowers have an average operating time of 930 minutes.
Thus, the overall duration for the three lawn mowers is 
The shortest time any mower runs is 900 minutes.
To find the longest operating time of any mower:
Let
represent the maximum operating time for any of the mowers.
Since any of the mowers works the longest time.
Consequently, the remaining two mowers operate at the minimum time.
Based on the question:


After subtracting 1800 from both sides:


Thus, the maximum potential operating time for any mower is 990 minutes.
Consequently, the answer is A. 990.
Is there additional information regarding the question?
To determine the interest, we need to apply the following formula: Interest = Principal x Rate x Time or I = PRT. Substitute the values: I = [$20 + ($10 x $34)] - 320 = $40. Here, P = $320, R =?, and T = 10 months/year. Since R is the unknown, we'll find it using the formula R = I/PT. This becomes R = ($20 + ($10 x $34) - 320) / ($320 x 10 months). T = 10 months/12 months = 0.83. Thus, R = ($40)/$320 x 0.83 which simplifies to R = 40/265.6, resulting in R = 15.06024096.
The triangles ADE and ABC are similar, thus the ratios of their corresponding sides are equal.
500 = 2.5x + 200, x denotes the number of desserts. Rearranging gives 500 - 200 = 2.5x, leading to 300 = 2.5x. Consequently, x = 120. Therefore, the answer is C.