Paula's dog has a weight of 36 pounds.
3.56 ± 0.011 = (3.549, 3.571). That is the answer.
Let X denote <span>the baby’s weight.
Let y represent </span>the doctor’s weight.
Let z stand for the nurse’s weight.
From the equations: x + y = 78 implies y = 78 - x
and x + z = 69 gives z = 69 - x
then we have x + y + z = 142
Substituting y = 78 - x and z = 69 - x into the equation x + y + z = 142
x + y + z = 142
x + 78 - x + 69 - x = 142
-x + 147 = 142
-x = -5
x = 5
Conclusion
<span>the baby’s weight was 5 kg</span>
Complete question;
A booster club financed pizzas for an end-of-season celebration. The cost was $13 for each pepperoni pizza and $11 for each plain pizza. They purchased a
total of 18 pizzas for the event, totaling $212.
Organize the numbers into an equation that represents this scenario with x being the number of pepperoni pizzas and y being the number of plain pizzas purchased.
Answer:
13x + 11y = 212
Step-by-step explanation:
Two varieties of pizza were purchased: pepperoni and plain. The pepperoni variety cost $13 each while the plain one cost $11 each. In total, they bought 18 pizzas.
The overall expenditure on the pizzas was $212.
total number of pizzas = 18
total amount spent on pizzas = $212
x represents the number of pepperoni pizzas
y represents the number of plain pizzas
The cost of the pepperoni pizzas is derived by multiplying the number of pizzas by their individual price. The same calculation applies for the plain pizzas.
Therefore, by summing the costs of both pizza types, we arrive at the total price for the pizzas.
13x + 11y = 212
