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kupik
2 months ago
5

The average rate of the first part of Yi’s walk on a park loop was 4 miles per hour. She then met up with a friend and the two w

alked the rest of the way at an average rate of 5 miles per hour. The entire 3-mile walk took Yi 42 minutes (0.7 hour). Which equation can be used to solve for x, the time in hours that Yi spent walking before meeting her friend?
Mathematics
2 answers:
Zina [12.3K]2 months ago
8 0
During this phase, she traveled at <span>4 miles per hour (x*4)

and for the remainder of the distance (which is 0.7-x, since the total time was 42 minutes, thus the rest equates to 0.7-x), her speed was 5 miles per hour - therefore the distance covered was (0.7-x)*5 m/h



. The overall distance totaled 3 miles, so by combining both distances, we arrive at this equation:

x*4+ (0.7-x)*5=3

removing the brackets gives us:

4x+0.7*5-5x=3
</span>
<span>4x+3.5-5x=3

subtracting 3.5 from each side yields:
4x-5x=3-3.5
-x=-0.5
 
multiplying both sides by (-1)
x=0.5:

therefore, she walked for half an hour by herself, which amounts to 30 minutes!</span>
Zina [12.3K]2 months ago
5 0

Response:

D, 4x + 5(0.7 – x) = 3.

Detailed explanation:

yw egen2020

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Translate into an algebraic expression and simplify if possible. C It would take Maya x minutes to rake the leaves and Carla y m
lawyer [12517]

Answer:

together they rake \frac{y+x}{xy} leaves in one minute.

Step-by-step explanation:

If Maya takes x minutes to rake, then in one minute, she rakes \frac{1}{x} leaves.

For Carla, if her raking takes y minutes, in one minute she rakes \frac{1}{y} leaves.

Thus, to find the amount they work together in one minute, we add both of their contributions for that minute, resulting in: \frac{1}{x}+ \frac{1}{y}

Finally, simplifying this expression gives:

\frac{1}{x}+ \frac{1}{y} =\frac{y+x}{xy}

As a result, they collectively rake \frac{y+x}{xy} leaves in a minute.

8 0
2 months ago
A high school theater club has 40 students, of whom 6 are left-handed. Two students from the club will be selected at random, on
babunello [11817]

Response:

1.92\%

Detailed explanation:

Probability for an event is calculated as the ratio of the size of the event space compared to that of the sample space.

The sample space encompasses all possible outcomes.

Event space represents the number of favorable outcomes for the event in question.

Thus

Let

x ------> size of event space

y ----- → size of sample space

so

P=\frac{x}{y}

Calculate the probability of the first student being left-handed

we have

x=6

y=40

substituting values

P=\frac{6}{40}

Simplify

P=\frac{3}{20}

Calculate the probability of the second student being left-handed

we have

x=6-1=5

y=40-1=39

substituting values

P=\frac{5}{39}

Calculate the probability that both selected students will be left-handed

Multiply the probabilities together.

P=\frac{3}{20}(\frac{5}{39})=\frac{15}{780}

Convert to percentage

Multiply by 100

\frac{15}{780}(100)=1.92\%

4 0
2 months ago
2 Tables. A 2-column table with 4 rows is titled Table 1. Column 1 has entries 2, 4, 6, 8. Column 2 has entries 3, 6, 9, 12. A 2
tester [12383]

Response:

2:3 is

✔ lesser than

5:6

10:12 is

✔ greater than

6:9

The ratios shown in Table 1 are

✔ smaller than

those in Table 2

Step-by-step explanation:

6 0
1 month ago
A battery with 20% percent of its full capacity is connected to a charger. Every minute that passes, an additional 5% percent of
Inessa [12570]

Response:

The connection between battery capacity and time is:

Y=0.05t+0.2

The associated graph is provided.

Step-by-step explanation:

We will plot the battery's charged capacity against time.

The charging rate remains steady; hence, the relationship is linear.

Initially, at time t=0, the battery's capacity measures 0.2 (or 20%).

With each passing minute, an additional 5% of its capacity is accumulated. Thus, at t=1, the capacity becomes 0.2 + 0.05 = 0.25 (or 25%).

We can derive the slope for the linear function as:

m=\dfrac{\Delta Y}{\Delta t}=\dfrac{0.05}{1}=0.05

Consequently, the correlation between battery capacity and time is:

Y=0.05t+0.2

3 0
2 months ago
Venetta buys 2 pounds of pistachios and 3 pounds of almonds. The pistachios cost $4 more per pound than the almonds. She pays a
babunello [11817]

Answer:

A. Combining one pound of pistachios with one pound of almonds costs $20.

C. Decreasing the almond quantity by one pound leads to a total price of $40.

E. The price p (in dollars) per pound of pistachios is represented by the equation 2p + 3(p – 4) = 48.

Step-by-step explanation:

Let:

x = cost per pound of pistachios

y = cost per pound of almonds

We know that

x = y + 4 (Equation A)

2x + 3y = 48 (Equation B)

Substitute x from Equation A into Equation B:

2(y + 4) + 3y = 48

2y + 8 + 3y = 48

5y = 48 – 8

y = 8

Find x:

x = 8 + 4 = 12

Therefore, pistachios cost $12 per pound and almonds cost $8 per pound.

Verify the statements:

Case A) One pound of each equals $20.

True, since 12 + 8 = 20.

Case B) Pistachios cost twice as much as almonds.

False, because 2 × 8 = $16 ≠ $12.

Case C) Reducing almond pounds by 1 yields $40 total.

True, as 2(12) + 2(8) = 24 +16 = 40.

Case D) The almond cost modeled by 2(a – 4) + 3a = 48.

False; it should be 2(a + 4) + 3a = 48.

Case E) The pistachio cost modeled by 2p + 3(p – 4) = 48.

True, since p = a + 4 implies a = p – 4.

8 0
3 months ago
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