A baby wriggled so much that weighing him at the clinic was a problem. So the doctor held the baby and stood on a scale. Then th

Question

1 month ago

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A baby wriggled so much that weighing him at the clinic was a problem. So the doctor held the baby and stood on a scale. Then th

e nurse held the baby and stood on the scale. Then the doctor held the nurse who held the baby and stood on the scale. the three results were 78 kg, 69 kg and 142 kg respectively. What was the weight of the baby.
Long question but help me out ( it was 69 kg I mean)

Mathematics

2 answers:

babunello [11.8K] · Answer 1 · 2026-04-05T02:26:58+03:00

Let X denote the baby’s weight.
Let y represent the doctor’s weight.
Let z stand for the nurse’s weight.

From the equations: x + y = 78 implies y = 78 - x
and x + z = 69 gives z = 69 - x
then we have x + y + z = 142

Substituting y = 78 - x and z = 69 - x into the equation x + y + z = 142

x + y + z = 142
x + 78 - x + 69 - x = 142
-x + 147 = 142
-x = -5
x = 5

Conclusion

the baby’s weight was 5 kg

AnnZ [12.3K] · Answer 2 · 2026-04-05T02:25:39+03:00

Let B represent the baby’s weight
N for the Nurse's weight 
D for the Doctor's weight

Setting up the equations gives us:

1. B + D = 78
2. B + N = 69
3. B + D + N = 142

Now taking equations 1 and 3:

From B + D = 78, we substitute 78 into the third equation where B + D exists
78 + N = 142 (what added to 78 will equal 142)
Thus, 78 + 64 = 142

The nurse weighs 64 kg

Next, we subtract 64 from the combined weight of the baby and nurse.

The baby’s weight is 5kg

Finally, using the combined weight of the doctor and baby and subtracting that gives the doctor’s weight:

The doctor weighs 73 kg

ANSWER:

The baby’s weight is 5kg, the nurse is 64, and the doctor is 74.

Apologies for the lengthy response, but I hope this clarifies matters.

A baby wriggled so much that weighing him at the clinic was a problem. So the doctor held the baby and stood on a scale. Then th

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