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Fofino
26 days ago
11

Determine the number of bytes necessary to store an uncompressed binary image of size 4000 × 3000 pixels

Computers and Technology
1 answer:
maria [879]26 days ago
3 0

Response: 1,500,000 bytes.

Clarification:

If we assume the image dimensions are 4000 pixels in width and 3000 pixels in height, the total uncompressed image will consist of 4000*3000= 12,000,000 pixels.

In the case of a binary image, each pixel can have only two values, which necessitates one bit for each pixel.

This indicates that we need to accommodate 12,000,000 bits.

Given that 1 byte equals 8 bits.

So, to store an uncompressed binary image sized 4000 x 3000 pixels, 12,000,000/8 bytes is required ⇒ 1,500,000 bytes.

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Explanation:

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Which decimal value (base 10) is equal to the binary number 1012?
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Answer:

The decimal representation of 101₂² from base 2 equals 25 in base 10.

Explanation:

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In this expression, we observe that the '2' in the hundred's place must be converted to '0' while carrying over '1' to the thousand's position, leading to;

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Next, we convert the outcome of squaring the base 2 number, 11001₂, into base 10 through the following method;

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