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aalyn
3 months ago
8

Implement the function couple, which takes in two lists and returns a list that contains lists with i-th elements of two sequenc

es coupled together. You can assume the lengths of two sequences are the same. Try using a list comprehension.
Computers and Technology
1 answer:
zubka84 [1K]3 months ago
7 0

Answer:

couple.py

def couple(s1,s2):

  newlist = []

  for i in range(len(s1)):

      newlist.append([s1[i],s2[i]])

  return newlist

s1=[1,2,3]

s2=[4,5,6]

print(couple(s1,s2))

enum.py

def couple(s1,s2):

  newlist = []

  for i in range(len(s1)):

      newlist.append([s1[i],s2[i]])

  return newlist

def enumerate(s,start=0):

  number_Array=[ i for i in range(start,start+len(s))]

  return couple(number_Array,s)

s=[6,1,'a']

print(enumerate(s))

print(enumerate('five',5))

Explanation:

You might be interested in
Write a program that prompts the user to enter three cities and displays them in ascending order. Here is a sample run: Enter th
amid [951]

Answer:

import java.util.Scanner;

public class SortStrings3 {

   public static void main(String args[]){

       Scanner scanner = new Scanner(System.in);

       String str1, str2, str3;

       System.out.print("Enter the first city: ");

       str1 = scanner.nextLine();

       System.out.print("Enter the second city: ");

       str2 = scanner.nextLine();

       System.out.print("Enter the third city: ");

       str3 = scanner.nextLine();

       System.out.print("The three cities in alphabetical order are ");

       if(str1.compareTo(str2) < 0 && str1.compareTo(str3) < 0){

           System.out.print(str1+" ");

           if(str2.compareTo(str3) < 0){

               System.out.print(str2+" ");

               System.out.println(str3);

           }

           else {

               System.out.print(str3+" ");

               System.out.println(str2);

           }

       }

       else if(str2.compareTo(str1) < 0 && str2.compareTo(str3) < 0){

           System.out.print(str2+" ");

           if(str1.compareTo(str3) < 0){

               System.out.print(str1+" ");

               System.out.println(str3);

           }

           else {

               System.out.print(str3+" ");

               System.out.println(str1);

           }

       }

       else{

           System.out.print(str3+" ");

           if(str1.compareTo(str2) < 0){

               System.out.print(str1+" ");

               System.out.println(str2);

           }

           else {

               System.out.print(str2+" ");

               System.out.println(str1);

           }

       }

   }

}

EXPLANATION:

The task requires creating a program that will prompt users to input three cities named Atlanta, Chicago, and Los Angeles (which are to be sorted in ascending alphabetical order).

Thus, we're going to develop the code using a programming language called JAVA (JUST ANOTHER VIRTUAL ACCELERATOR).

We chose Java for this task because it is capable of loading, validating, and executing code on either single or multiple servers.

The code can be found in the attached document/file. Please take a look at it.

Download doc
3 0
2 months ago
The engineering firm you work for is submitting a proposal to create an amphitheater at a state park. Proposals must be submitte
Rzqust [1037]
Accessibility is defined as the availability of data to individuals and resources that may have disabilities regarding access, in the context of technical communication. Various regulations exist to create accessible documentation. Section divider tabs and indexes are included in every proposal binder, ensuring every member can understand the proposal's content. Thus, all individuals can access the three-ring binder to gain information about the amphitheater's creation.
8 0
2 months ago
a.Write a Python function sum_1k(M) that returns the sum푠푠= ∑1푘푘푀푀푘푘=1b.Compute s for M = 3 by hand and write
8_murik_8 [964]
def sum_1k(M): s = 0 for k in range(1, M+1): s = s + 1.0/k return s def test_sum_1k(): expected_value = 1.0+1.0/2+1.0/3 computed_value = sum_1k(3) if expected_value == computed_value: print("Test is successful") else: print("Test is NOT successful") test_sum_1k() It appears that the hidden portion involves summing (sigma) from 1 to M with the term 1/k. Accordingly, within sum_1k(M), one should iterate from 1 to M to compute and return the sum of the expression. The test_sum_1k() function calculates the expected_value, an accurate hand-calculated value, while computed_value denotes the result of sum_1k(3). The values are then compared and an appropriate message is printed. Finally, invoke test_sum_1k() to observe the result.
8 0
1 month ago
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