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Aleksandr-060686
2 months ago
15

The time it takes a printer to print a job is an Exponential random variable with the expectation of 12 seconds. You send a job

to the printer at 10:00 am, and it appears to be third in line. What is the probability that your job will be ready before 10:01
Mathematics
1 answer:
Leona [12.6K]2 months ago
8 0

Answer:

0.8753

Step-by-step explanation:

Determine the likelihood that your job will complete before 10:01 am.

In this scenario, the expected value of an Exponential distribution is E(X)=12.

To find the probability for the third job, we apply the Poisson Distribution with a parameter of 1/λ.

This gives us E(Y) =1/12.

Since the third job is expected to be ready by 10:01 AM, we have E(Y)=61/12.

Hence, the probability sought is

P(X\geq 3)=1-P(X

=1- POISSON(3,5,true)

=1-0.1246

=0.8753

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The calculation needed to find the cost of the factory tour was $5(29 students). Melissa used the expression $5(20 + 9). Mrs. Ga
AnnZ [12381]
Honestly, I find Mrs. Garcia's method easier to perform mentally. It hinges on how familiar you are with your multiples of 5. (5*15 = 75 is a multiplication I often use)

Melissa's approach involves calculating 5*20 = 100 and 5*9 = 45, then combines the 3-digit result 100 with the 2-digit result 45, yielding 145. Adding 45 to 00 is simple and doesn’t require carrying digits, thus the arithmetic is fairly straightforward.

Mrs. Garcia's technique involves computing 5*14 = 70 and 5*15 = 75, then summing these two-digit results. Many people may not readily recall that 5*15=75, which complicates forming that product. The addition of 70 and 75 requires a carrying operation, making the math somewhat more complex. The resulting total is 145.

(The rationale behind my preference for Mrs. Garcia's method is that I can achieve the final sum by simply doubling 7 tens, followed by adding 5. The only 3-digit number to remember mentally is the ultimate total.)

_____Subtraction introduces a slight complication, yet reshaping it as $5(30 -1) = $150 - 5 = $145 is possible.
Or, you may reframe it as $5(28 +1) = $140 +5 = $145.
Dividing an even number by 2 to find the product of 5 is straightforward when you append a zero.
  5*14 = 10*7 = 70
  5*28 = 10*14 = 140.
7 0
2 months ago
Read 2 more answers
for the level 3 course, examination hours cost twice as much as workshop hours and workshop hours cost twice as much as lecture
Leona [12618]

Answer:

The hourly rate for lectures is $7.33

Step-by-step explanation:

* Let's break down how to tackle the problem.

- For the level 3 course, examination hours are priced at double that of workshop hours.

- Workshop hours cost twice the rate of lecture hours.

- The total includes examination, workshop, and lecture hours.

- Examination lasts 3 hours, workshops 24 hours, and lectures 12 hours.

* Let’s denote the cost of lecture hours as $x per hour.

∴ The lectures cost $x per hour.

∵ Workshop charge is twice that of lectures

∴ Workshop hours cost 2(x) = 2x per hour.

∵ Examination fees are double that of workshop hours

∵ The workshop cost is 2x

∴ Examination fees are 2(2x) = 4x per hour.

- Combining costs for level 3 gives us the total of lecture, workshop, and examination hours.

∵ 12 hours for lectures

∵ 24 hours for workshops

∵ 3 hours for examinations

∵ Thus the total cost for level 3 = 12(x) + 24(2x) + 3(4x).

∴ Total cost for level 3 = 12x + 48x + 12x.

∵ Therefore, total cost = $528.

∴ 12x + 48x + 12x = 528.

∴ 72x = 528; hence we divide both sides by 72.

∴ x = 7.33.

∵ x represents the cost of lecture hours per hour.

∴ Therefore, the hourly price for lectures is $7.33.

6 0
3 months ago
A family purchases a car for $11,000 which depreciates about 16% annually. How much is the car worth after 4 years
PIT_PIT [12445]

11,000 multiplied by 16% equals $1,750, which when multiplied by 4 gives a total of $7,040.

Therefore, after 4 years, the car's value is $11,000 - 7,040 = $3,960.

7 0
3 months ago
Read 2 more answers
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