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REY
2 days ago
6

What is the following product? RootIndex 3 StartRoot 16 x Superscript 7 Baseline EndRoot times RootIndex 3 StartRoot 12 x Supers

cript 9 Baseline EndRoot x squared (RootIndex 3 StartRoot 28 x squared EndRoot) x Superscript 5 Baseline (RootIndex 3 StartRoot 28 x EndRoot) 4 x squared (RootIndex 3 StartRoot 3 x squared EndRoot) 4 x Superscript 5 Baseline (RootIndex 3 StartRoot 3 x EndRoot)
Mathematics
1 answer:
Inessa [9K]2 days ago
6 0

Response:

\sqrt[3]{16x^7} * \sqrt[3]{12x^9} = {4 x^{5}\sqrt[3]{3x} }

Detailed explanation:

Starting with

\sqrt[3]{16x^7} * \sqrt[3]{12x^9}

Given data

Find the products

Using the laws of indices;

\sqrt[m]{a} * \sqrt[m]{b} = \sqrt[m]{a*b}

Therefore;

\sqrt[3]{16x^7} * \sqrt[3]{12x^9} = \sqrt[3]{16x^7 * 12x^9}

\sqrt[3]{16x^7} * \sqrt[3]{12x^9} = \sqrt[3]{16* x^7 * 12 * x^9}

\sqrt[3]{16x^7} * \sqrt[3]{12x^9} = \sqrt[3]{16*12* x^7 * x^9}

From the laws of indices

a^m * a^n = a^(m+n); So,

\sqrt[3]{16x^7} * \sqrt[3]{12x^9} = \sqrt[3]{16*12* x^{7+9}}

\sqrt[3]{16x^7} * \sqrt[3]{12x^9} = \sqrt[3]{16*12* x^{16}}

Calculate 16 * 12

\sqrt[3]{16x^7} * \sqrt[3]{12x^9} = \sqrt[3]{4*4*4*3* x^{16}}

\sqrt[3]{16x^7} * \sqrt[3]{12x^9} = \sqrt[3]{4^3 *3* x^{16}}

Using the laws of indices

a^{\frac{1}{m}} = \sqrt[m]{a}

Thus;

\sqrt[3]{16x^7} * \sqrt[3]{12x^9} = {4^3 *3* x^{16}})^{\frac{1}{3}}

\sqrt[3]{16x^7} * \sqrt[3]{12x^9} = {4^{3*{\frac{1}{3}}} *3^{{\frac{1}{3}}}* x^{16*{\frac{1}{3}}}})

\sqrt[3]{16x^7} * \sqrt[3]{12x^9} = {4 *3^{{\frac{1}{3}}}* x^{\frac{16}{3}}}

Divide 16 by 3 (Express as a mixed number)

\sqrt[3]{16x^7} * \sqrt[3]{12x^9} = {4 *3^{{\frac{1}{3}}}* x^{5\frac{1}{3}}}

Split mixed numbers

\sqrt[3]{16x^7} * \sqrt[3]{12x^9} = {4 *3^{{\frac{1}{3}}}* x^{5+\frac{1}{3}}}Apply laws of indices

Rearrange

\sqrt[3]{16x^7} * \sqrt[3]{12x^9} = {4 *3^{{\frac{1}{3}}}* x^{5}*{x ^\frac{1}{3}}}

Apply laws of indices

\sqrt[3]{16x^7} * \sqrt[3]{12x^9} = {4 * x^{5}*3^{{\frac{1}{3}}}*{x ^\frac{1}{3}}}

\sqrt[3]{16x^7} * \sqrt[3]{12x^9} = {4 x^{5}*3^{{\frac{1}{3}}}*{x ^\frac{1}{3}}}

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Answer:

A

Step-by-step explanation:

To construct the perpendicular bisector, follow these steps:

Step 1:

Set the compass to a distance greater than half the length of segment AB, place it on point A, and draw an arc across AB.

Step 2:

Keeping the same width, place the compass on point B and create another arc across AB.

Step 3:

With the ruler, connect the two intersection points of the arcs by drawing a line.

Step 4:

This line will be the perpendicular bisector of the segment AB.

Thus, option A is the correct choice.

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"The difference between five-halves of a number<br> and 17 is 48."
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Let the number be x. The equation x/5 - 17 = 48 leads to (x - 85)/5 = 48. Multiplying gives x - 85 = 240, so x = 240 + 85, resulting in x = 325.
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8 days ago
Kim's business earns $10,000 per month. Kim's non-employee expenses are $3,000 per month. If Kim wants $2,000 in profit per mont
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Response:

The monthly income of Kim's business is $10,000.

Every month, Kim spends $3,000 on non-employee costs.

To achieve a monthly profit of $2,000, the highest possible expenditure for employees is calculated as follows:

10000 - 3000 - 2000 = 5000

With the cost of each employee being $1,000 a month, Kim can hire a maximum of 5000/1000 = 5 employees.

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In July, the average temperature in one US city was 29°C. By December, the average temperature had fallen by 29°C. Explain why t
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Mike runs for the president of the student government and is interested to know whether the proportion of the student body in fa
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Answer:

We conclude that less than or equal to 50% of the student body supports him significantly.

Step-by-step explanation:

Mike, while campaigning for the student government presidency, is keen to determine if more than 50% of the student body supports him.

A random sample of 100 students was surveyed, with 55 expressing support for Mike.

Let p = the proportion of students backing Mike.

Thus, Null Hypothesis, H_0: p \leq 50% {indicating that the proportion of supporters among the student body is significantly less than or equal to 50%}

Alternate Hypothesis, H_A: p > 50% {indicating that the proportion of supporters among the student body is significantly more than 50%}

The test statistics to be utilized here One-sample z proportion statistics;

T.S. = \frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } } ~ N(0,1)

where, \hat p = the sampled proportion in favor of Mike = \frac{55}{100} = 0.55

n = number of sampled students = 100

Therefore, test statistics = \frac{0.55-0.50}{\sqrt{\frac{0.55(1-0.55)}{100} } }

= 1.01

The z test statistic is 1.01.

At a significance level of 0.05, the z table provides a critical value of 1.645 for a right-tailed test.

Given that our test statistic falls below the critical value of z (1.01 < 1.645), we lack sufficient evidence to reject the null hypothesis as it remains outside the rejection region, leading to failure to reject our null hypothesis.

As a result, we conclude that less than or equal to 50% of the student body is in favor of him or the proportion supporting Mike is not significantly greater than 50%.

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25 days ago
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