Response:
6 hours worked as a tutor
Detailed clarification:
40 x 9.25 = 370$
425 - 370 = 55
55/10 = 5.5
so 5.5 but since you work a full hour, round up to 6 hours worked as a tutor
x = 27 + 3 √ 129/ 4, 27 − 3 √ 129/ 4
Please note: the entire equation mentioned is divided by 4, not only the last term.
x approximates to 15.26836251, − 1.76836251
That concludes my response. I hope this is helpful. You will still need to work on finding y and z, which can be quite challenging:)
Answer:


Step-by-step explanation:
Step 1:-
We have c1(t) = e^ t i + (sin(t))j + t³k
and c2(t) = e^−t i + (cos(t))j − 6t³k.
By adding c1(t) and c2(t):
c1(t)+c2(t) = e^ t i + (sin(t))j + t³k + e^−t i + (cos(t))j − 6t³k
Now, employing the derivative formula:


Next, differentiate with respect to 't'

By factoring out i, j, and k terms, we arrive at:
