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AysviL
2 months ago
14

The function f(x)=startroot -x endroot is shown in the graph. Which statement is correct?

Mathematics
2 answers:
tester [12.3K]2 months ago
8 0

Answer:

B. The graph's domain includes all real numbers that are less than or equal to 0

Step-by-step explanation:

To begin, we determine the domain as follows:[

(negative infinity, 0} or All real numbers ≤ 0

Next, we address the range.

[[0, positive infinity) or All real numbers ≥ 0

Immediately, we can discard options A, C, and D. This narrows us down to choice B. as the appropriate answer.

babunello [11.8K]2 months ago
6 0

Answer:

It's d

Step-by-step explanation:

I sacrificed myself for the responses

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3 0
2 months ago
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Write the equation of the line that is parallel to the line y=−14x−3 through the point (4,4). A. y=x+5 B. y=−14x+5 C. y=5x+1 D.
Svet_ta [12734]
None of the provided options appear to be accurate. The equation resembles y = mx + b, identifying m as the slope and b as the y-intercept. Here, m = -14. Parallel lines maintain the same slope, resulting in the new line's slope of -14. To find the y-intercept, we substitute x = 4 and y = 4 into the equation. Consequently: 4 = (-14)(4) + b. By solving for b, we find b = 60. Therefore, the new line's equation is y = -14x + 60.
6 0
1 month ago
Triangles ΔABC ≅ ΔBAD so that C and D lie in the opposite semi-planes of segment AB. Prove that segment CD bisects segment AD.
Zina [12379]

Answer:

Review the explanation

Step-by-step explanation:

The triangles ΔABC and ΔBAD are congruent, establishing:

  • AB ≅ BA;
  • AC ≅ BD;
  • BC ≅ AD;
  • ∠ABC ≅ ∠BAD;
  • ∠BCA ≅ ∠ADB;
  • ∠CAB ≅ ∠DBA.

Now, consider triangles AEC and BED. In these triangles, we have:

  • AC ≅ BD;
  • ∠EAC ≅ ∠EBD (due to ∠CBA ≅ ∠BAD);
  • ∠AEC ≅ ∠BED (being vertical angles).

Therefore, ΔAEC ≅ ΔBED, which leads to the conclusion that:

AE ≅ EB.

This indicates that line segment CD bisects segment AD.

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2 months ago
Triangle L M N is cut by line segment O P. Line segment O P goes from side M L to side M N. The length of O L is 14, the length
babunello [11817]
The value of y that would ensure OP runs parallel to LN is 36. Step-by-step explanation: This pertains to the concept of similar triangles. The diagram based on the provided data is attached. Given: The length of OL is 14, OM is 28, MP is y, and PN measures 18. The total length of MN is the combination of MP and PN, expressed as y + 18. The length ML is calculated as MO plus OL, giving us 28 + 14 = 42. For OP to be parallel to LN, the ratio MO to ML must equal MP to PN, formulated as MO/ML = 28/42 and MP/PN= y/(y+18). By equating both ratios 28/42 = y/(y+18), it simplifies to 42y = 28(y + 18). Solving for y leads to 42y being equal to 28y + 504, resulting in 14y = 504. Thus, y equals 504/14 = 36.
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1 month ago
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