Answer:
la derivada de la función vectorial dada es = ( -16-22t, 14-36t, -2-16t )
Explicación paso a paso:
datos proporcionados:
función vectorial: r(t) = ta*(b+tc)
a = ( 2,-3.4). b = (-4,5,-1). c = ( -2,-1,5)
para determinar la derivada de la función vectorial, se procederá a diferenciar respecto a x; aquí está la solución detallada
Answer:
He is dividing the angle BAC into two equal parts.
Step-by-step explanation:
Initially, he places the compass at point A and draws two small arcs intersecting points D and E. Next, setting the compass at D and then at E, he draws two arcs that intersect between the line segments AB and AC.
The bisecting line is drawn from point A through the intersection of these arcs.
Answer:
Answer and Explanation:
We have:
Population mean,
μ
=
3
,
000
hours
Population standard deviation,
σ
=
696
hours
Sample size,
n
=
36
1) The standard deviation for the sampling distribution:
σ
¯
x
=
σ
√
n
=
696
√
36
=
116
2) By the central limit theorem, the sampling distribution's expected value matches the population mean.
Thus:
The expected value of the sampling distribution equals the population mean,
μ
¯
x
=
μ
=
3
,
000
The standard deviation of the sampling distribution,
σ
¯
x
=
116
The sampling distribution of
¯
x
is roughly normal due to a sample size greater than
30
.
3) The likelihood that the average lifespan of the sample falls between
2670.56
and
2809.76
hours:
P
(
2670.56
<
x
<
2809.76
)
=
P
(
2670.56
−
3000
116
<
z
<
2809.76
−
3000
116
)
=
P
(
−
2.84
<
z
<
−
1.64
)
=
P
(
z
<
−
1.64
)
−
P
(
z
<
−
2.84
)
=
0.0482
In Excel: =NORMSDIST(-1.64)-NORMSDIST(-2.84)
4) The probability of the average life in the sample exceeding
3219.24
hours:
P
(
x
>
3219.24
)
=
P
(
z
>
3219.24
−
3000
116
)
=
P
(
z
>
1.89
)
=
0.0294
In Excel: =NORMSDIST(-1.89)
5) The likelihood that the sample's average life is lower than
3180.96
hours:
P
(
x
<
3180.96
)
=
P
(
z
<
3180.96
−
3000
116
)
=
P
(
z
<
1.56
)
=
0.9406
Answer:
The main aspects are
50ft³ = volume
0.5ft³/min = filling rate
Time= 100 minutes
Step-by-step breakdown:
Chiang is in the process of filling a 50ft container with water at a speed of 0.5 ft/min.
50ft³ = volume
0.5ft³/min = flow rate
It’s important to note that we still need to determine how long it will take to fill the 50 ft³ container.
Time = volume / rate
Time = 50 ft³ / 0.5 ft³/min
Time = 50 / 0.5 min
Time = 100 min
The main aspects are
50ft³ = volume
0.5ft³/min = filling rate
Time= 100 minutes
Answer:
a) 0.00019923%
b) 47.28%
Step-by-step explanation:
a) To determine the likelihood that all sockets in the sample are defective, we can use the following approach:
The first socket is among a group that has 5 defective out of 38, leading to a probability of 5/38.
The second socket is then taken from a group of 4 defective out of 37, following the selection of the first defective socket, resulting in a probability of 4/37.
Extending this logic, the chance of having all 5 defective sockets is computed as: (5/38)*(4/37)*(3/36)*(2/35)*(1/34) = 0.0000019923 = 0.00019923%.
b) Using similar reasoning as in part a, the first socket has a probability of 33/38 of not being defective as it's chosen from a set where 33 sockets are functionally sound. The next socket has a proportion of 32/37, and this continues onward.
The overall probability calculates to (33/38)*(32/37)*(31/36)*(30/35)*(29/34) = 0.4728 = 47.28%.
