A Statistics class is estimating the mean height of all female students at their college. They collect a random sample of 36 fem

Answer:

14110

Step-by-step explanation:

Let x = number of pages;

μ = 12200; σ = 820

Zscore = (x - μ) / σ

Zscore = (x - 12200) / 820

Zcritical for 99% confidence, with a one-tailed test equals 2.33

Hence, Z at 99% = 2.33

Substituting in for Zscore = 2.33

Zscore = (x - 12200) / 820

2.33 = (x - 12200) / 820

2.33 * 820 = x - 12200

1910.6 = x - 12200

1910.6 + 12200 = x

x = 14110.6

x = 14111

The number of pages to advertise for the cartridge is 14,110

Let the events be defined as follows:
A=Nathan suffers from an allergy
~A=Nathan does not suffer from an allergy
T=Nathan receives a positive test result
~T=Nathan does not receive a positive test result

According to the provided data,
P(A)=0.75 [ probability indicating that Nathan is allergic ]
P(T|A)=0.98 [ probability of obtaining a positive test result if Nathan is allergic to Penicillin]

We aim to calculate the probability that Nathan is both allergic and tests positive
P(T n A)

Using the definition of conditional probability,
P(T|A)=P(T n A)/P(A)
By substituting the known values,
0.98 = P(T n A) / 0.75
We then solve for P(T n A)
P(T n A) = 0.75*0.98 = 0.735

Hope this assists you!!