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lina2011
17 days ago
5

A Statistics class is estimating the mean height of all female students at their college. They collect a random sample of 36 fem

ale students and measure their heights. The mean of the sample is 65.3 inches. The standard deviation is 5.2 inches. Use the T-distribution Inverse Calculator applet to answer the following question. What is the 90% confidence interval for the mean height of all female students in their school?
a. (56.5, 74.1)
b. (63.6, 67.0)
c. (63.8, 66.8)
d. (63.9, 66.7)
Mathematics
1 answer:
Inessa [9K]17 days ago
4 0

Response:

d. (63.9, 66.7)

This indicates that the 90% confidence interval is (a,b) = (63.9, 66.7)

Detailed explanation:

A confidence interval refers to a set of values within which there's a defined probability that a parameter’s value falls.

The formula for confidence interval in statistics can be represented as:

x +/- zr/√n

Here, we have;

Mean x = 65.3

Standard deviation r = 5.2

Sample size n = 36

Confidence interval level = 90%

z (for 90% confidence) = 1.645

Substituting our values gives us;

65.3 +/- 1.645(5.2/√36)

65.3 +/- 1.645(0.866667)

65.3 +/- 1.42567

65.3 +/- 1.4

Results in (63.9, 66.7)

This confirms that for a 90% confidence interval, (a,b) = (63.9, 66.7)

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An electronic product contains 40 integrated circuits. The probability that any integrated circuit is defective is 0.01, and the
Zina [9171]

Answer:

The chance that there is one or more defective integrated circuits is 33.10%.

Detailed solution:

Each integrated circuit can be either defective or not, which provides only two possible outcomes. As a result, this scenario is well-suited to be analyzed using the binomial probability distribution.

About the binomial distribution

This distribution calculates the likelihood of exactly x successes in n repeated trials where each trial has two possible results.

P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}

Here, C_{n,x} represents the count of combinations of x items selected from n elements, described by the formula:

C_{n,x} = \frac{n!}{x!(n-x)!}

And \pi is the probability of the event X occurring.

Applying it to the problem

The product contains 40 integrated circuits, so n = 40.

The probability that an individual integrated circuit is defective is 0.01, so \pi = 0.01.

Finding the probability of at least one defective circuit

There are two cases: either at least one integrated circuit is defective (probability P(X > 0)) or none are defective (probability P(X = 0)). Since probabilities sum to 1, we want to determine P(X>0).

P(X > 0) + P(X = 0) = 1

P(X > 0) = 1 - P(X = 0)

P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}

P(X = 0) = C_{40,0}.(0.01)^{0}.(0.99)^{40} = 0.6690

P(X > 0) = 1 - P(X = 0) = 1 - 0.6690 = 0.3310

Hence, the probability of having one or more defective integrated circuits is 33.10%.

3 0
1 month ago
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<span>Let A = a3b + 9a2b2 - 4ab5, and B = a3b - 3a2b2 + ab5. The difference can be expressed as A - B = a3b + 9a2b2 - 4ab5 - (a3b - 3a2b2 + ab5). When the negative sign is in front of the parentheses, all the internal signs change: this leads to: A - B = a3b + 9a2b2 - 4ab5 - a3b + 3a2b2 - ab5 = a3b - a3b + 9a2b2 + 3a2b2 - 4ab5 - ab5 = 12a2b2 - 5ab5. The first term’s degree is 2 + 2 = 4, while the second term’s degree is 1 + 5 = 6. Thus, the correct response is that the difference is a binomial of degree 6.</span>
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19 days ago
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lawyer [9240]

Answer:

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Explicación paso a paso:

datos proporcionados:

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