Segment JK has a length of 4.5 units. If segment LM has end points of L (3,1) and M (-1,4), how much longer than segment JK is s

Question

Stolb23

17 days ago

10

Segment JK has a length of 4.5 units. If segment LM has end points of L (3,1) and M (-1,4), how much longer than segment JK is s

egment LM?

Mathematics

2 answers:

lawyer [9.2K] · Answer 1 · 2026-03-10T23:59:06+03:00

Answer:

Segment LM measures 0.5 units longer than segment JK.

Step-by-step explanation:

It is known that segment JK has a length of 4.5 units, while segment LM has end points L (3,1) and M (-1,4).

To determine the length of segment LM, we will apply the distance formula.

$D=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Plugging in the known values:

$D=\sqrt{(3-(-1))^2+(1-4)^2}$

$D=\sqrt{(3+1)^2+(-3)^2}$

$D=\sqrt{(4)^2+(-3)^2}$

$D=\sqrt{16+9}$

$D=\sqrt{25}$

$D=5$

Thus, the length of segment LM is 5 units.

Next, we will calculate the difference in length between segment LM and JK as follows:

$\text{Difference between LM and JK}=5-4.5$

$\text{Difference between LM and JK}=0.5$

Consequently, segment LM is 0.5 units longer than segment JK.

Leona [9.2K] · Answer 2 · 2026-03-10T23:59:42+03:00

Leona [9.2K]17 days ago

4 0

Distance formula:
$d= \sqrt{ (x_{2}-x_{1}) ^{2}+( y_{2} - y_{1} )^{2}}\\ d= \sqrt{ (3-(-1)) ^{2}+(1 - 4 )^{2}}\\ d= \sqrt{ (4) ^{2}+(-3)^{2}}\\ d=\sqrt{16+9}\\ d=\sqrt{25}\\ d=5$

5 units-4.5 units=0.5 units

Segment LM exceeds segment JK by 0.5 units.