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scZoUnD
17 days ago
15

if Marianne's father calls and says he needs 13 pounds of potting soil, how many additional bags should she buy?

Mathematics
2 answers:
Leona [9.2K]17 days ago
5 0
THE RESULT WOULD BE 10 MORE BAGS
Inessa [9K]17 days ago
4 0

The solution is: 10 bags.

Here’s how to solve it:

16 × 5/8 = 80/8

80/8 results in 10

I hope this assists you!!! Best of luck!!!;)

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In the diagram, AB and EF are horizontal lines and CB is a vertical line segment. If FB : FC = 4 : 3, what are the coordinates o
Inessa [9000]
In response to the earlier inquiry, the diagram depicts horizontal lines along with a vertical segment; FB measures 3. If C is defined as 3, then the coordinates for point D would be (-6,-4). I trust this response has clarified your question.
8 0
17 days ago
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Clara lends half her collection of formal dresses, d, to her sister, Susan. Clara then buys four more dresses. If she has 12 now
Inessa [9000]

Answer:

16

Step-by-step explanation:

a:2+4 =12

a:2=12-4

a:2=8

a=8 ×2

a=16 dresses

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17 days ago
Last year the cost of a season ticket for a Rugby club was £370
AnnZ [9099]
8 over 45.

I hope this was helpful.
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17 days ago
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El perímetro de un rectángulo es 28cm, uno de los lados es 6cm más que el otro lado. Hallar el mayor lado del rectángulo.
Inessa [9000]

Answer: El lado mayor del rectángulo mide 10cm

Step-by-step explanation:

El perímetro de un rectángulo está dado por:

P = 2*L + 2*A

Donde L es la longitud y A es el ancho.

Como sabemos que un lado es 6cm más largo que el otro, podemos expresar esto como:

L = A + 6cm.

Por lo tanto, P = 28cm = 2*L + 2*A

Sustituyendo la primera ecuación en la segunda tenemos:

28cm = 2*(A + 6cm) + 2*A

28cm = 12cm + 4*A

28cm - 12cm = 4*A

16cm/4 = A

4cm = A.

Así que el ancho es 4 cm y la longitud se calcula como L = 4cm + 6cm = 10cm

4 0
1 month ago
Solve the following quadratic equations by extracting square roots.Answer the questions that follow.
babunello [8412]

Answer:

1. x=±4

2. t=±9

3. r=±10

4. x=±12

5. s=±5

Step-by-step explanation:

1. x^2 = 16

By extracting the square root on both sides

\sqrt{x^2}=\sqrt{16}\\\sqrt{x^2}=\sqrt{(4)^2}\\

x=±4

2. t^2=81

Again, take the square root of each side

\sqrt{t^2}=\sqrt{81}\\\sqrt{t^2}=\sqrt{(9)^2}

t=±9

3. r^2-100=0

r^{2}-100=0\\r^2 =100\\Taking\ Square\ root\ on\ both\ sides\\\sqrt{r^2}=\sqrt{100}\\\sqrt{r^2}=\sqrt{(10)^2}

r=±10

4. x²-144=0

We rewrite as x²=144

Applying square roots

\sqrt{x^2}=\sqrt{144}\\\sqrt{x^2}=\sqrt{(12)^2}

x=±12

5. 2s²=50

\frac{2s^2}{2} =\frac{50}{2}\\s^2=25\\Taking\ Square\ root\ on\ both\ sides\\\sqrt{s^2}=\sqrt{25}\\\sqrt{s^2}=\sqrt{(5)^2}

s=±5 ..

4 0
1 month ago
Read 2 more answers
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