Answer:
You need to multiply the denorminator both sides in order to form x note the subject:
Response: 8n
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Clarification:
The two sides, 4n+5 and 5n+6, comprise terms 4n and 5n which total to 9n. We require 8n to add to this to achieve 17n. In simpler terms, 4n + 5n + 8n = 9n + 8n = 17n
That is the reason why the outcome is 8n. There are no additional terms because the "+5" and "+6" in the two given expressions (4n+5 and 5n+6) sum to 5+6 = 11, matching what we aim for in the perimeter expression 17n + 11
Side 1 = 4n + 5
Side 2 = 5n + 6
Side 3 = 8n
Perimeter = (side1) + (side2) + (side3)
Perimeter = (4n + 5) + (5n + 6) + (8n)
Perimeter = 4n + 5 + 5n + 6 + 8n
Perimeter = (4n + 5n + 8n) + (5 + 6)
Perimeter = 17n + 11
So this confirms we possess the correct expression for the third side that is missing.
To tackle the problem, the general approach is to convert all measurements into the smallest unit possible.
a. 3 km 9 hm 9 dam 19 m + 7 km 7 dam
3,000 m 900 m 90 m 19 m + 7,000 m 70 m = 4,009 + 7,070 = 11,079 m
b. 5 sq.km 95 ha 8,994 sq.m + 11 sq. km. 11 ha 9,010 sq. m.
5,000,000 sq m 95,0000 sq m 8,994 sq m + 11,000,000 sq m 110,000 sq
9,010 sq m
5,103,994 sq m + 11,119,010 sq m = 16,223,004 sq m
c. 44 m - 5 dm
44 m - 0.5 m = 43.5 m
d. 73 km 47 hm 2 dam - 11 km 55 hm
73,000 m 4,700 m 20 m - 11,000 m 5,500 m
77,720 m - 16,500 m = 61,220 m
Answer:
In approximately 81 days, it is likely that the teacher on bus duty will be certified in CPR
Step-by-step explanation:
The probability of a teacher obtaining certification in Cardio-Pulmonary Resuscitation (CPR) is as follows:
36 out of 80
Hence
In a school year lasting 180 days, how many days can we anticipate that the teacher on bus duty will likely have CPR certification?
45% of the time
0.45 multiplied by 180 results in 81 days
In approximately 81 days, it is likely that the teacher on bus duty will be certified in CPR
{chocolate, strawberries, peanuts} Explanation: Given three sets, let A = {vanilla, chocolate, hot fudge, strawberries, sprinkles, peanuts, whipped cream}, let B = {vanilla, hot fudge, sprinkles, whipped cream}, and let C = {chocolate, hot fudge, peanuts, whipped cream}. Thus, the universal set U = A ∪ B ∪ C = {vanilla, chocolate, hot fudge, strawberries, sprinkles, peanuts, whipped cream}. B' consists of the elements found in U but not in B, which results in: {chocolate, strawberries, peanuts}.
