Answer:
1128.
Explanation:
The phenotype for dominant tasters is 1482.
The phenotype for recessive tasters = 2400 – 1482 = 918.
Recessive phenotypes = 2400 – 1482 = 918.
The frequency of the recessive phenotype = q² = 918 / 2400 = 0.38.
The frequency of the recessive allele q = √0.38 = 0.62.
For the dominant allele frequency, p = 1-q = 1- 0.62 = 0.38.
The heterozygous frequency = 2pq = 2 × 0.38 × 0.62 = 0.47.
The number of heterozygous individuals within the population = 0.47 × 2400 = 1128.
Thus, the result is 1128.
1. rivers and streams 2. groundwater seepage
To fix a thymine dimer via nucleotide excision repair, the sequence of enzyme activity is Endonuclease, DNA polymerase I, and DNA ligase. Two primary methods exist for repairing thymine dimers; one is photoreactivation, where an enzyme activated by blue light repairs the dimer, thus restoring the proper base pairing. The alternative method is excision repair, involving the uvr system that removes the dimer, with the gap filled by DNA polymerase I's proofreading capability.
