Simplify the given expression, using only positive exponents. Then complete the statements that follow. [ (x2y3)−1 (x−2y2z)2 ] 2

Question

17 days ago

9

, x ≠ 0, y ≠ 0, z ≠ 0. The exponent on x is . The exponent on y is . The exponent on z is .

2 answers:

babunello [8.4K] · Answer 1 · 2026-03-11T08:28:05+03:00

5 0

x=4

y=14

z=4

the commenter was correct

AnnZ [9.1K] · Answer 2 · 2026-03-11T08:24:07+03:00

Answer: y²z⁴ / x¹²

Explanation:

1) The expression to simplify:

$((x^2y^3)^{-1}(x^{-2}y^2z)^2)^2$

2) Rule: power of a power:

$(x^{-4}y^{-6})(x^{-8}y^8z^4)$

3) Rule: product of powers with identical bases

$x^{(-2-8)}y^{(-6+8)}z^4$

4) Add up the exponents

$x^{-12}y^2z^4$

5) Transfer the negative exponent to the denominator:

$\frac{y^2z^4}{x^{12}}$

The exponent attached to x is 12, for y it is 2, and for z it is 4.