Kevin cycles 18 miles every morning as part of his exercise. The time it takes him to complete the distance varies inversely as

Refer to the diagram illustrated below.

The specified constraints are
(a) y ≥ 24 ft
(b) x ≤ 10 ft
(c) y ≥ 3x
(d) y ≤ 33 ft
The shaded area represents the permissible region.

A (0, 33) meets all criteria
B (4, 36) does not satisfy condition (d)
C (4.8, 30.5) meets all criteria
D (9, 26) does not meet condition (c)
E (2, 22) does not satisfy condition (a)

Response:
The valid points are A and C.

The required work to pump water is 3,325,140 Joules. Step-by-step explanation: Work done by the pump is calculated by multiplying the force exerted on the pump by the distance the water is moved. Force equates to mass multiplied by gravitational acceleration. Consequently, Force = (water density × tank volume) × gravitational acceleration, leading to F = ρVg. Therefore, Work done = (ρVg) * d. Given the values of ρ = 1000 kg/m³, g = 9.8 m/s², d = 3 m, we compute the work done: Work = 1000 * 113.10 * 9.8 * 3 = 3,325,140 Joules.