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Hunter-Best
1 month ago
7

Easton bought 8 chicken wings for $8.80. How much would it cost for 17 wings?

Mathematics
2 answers:
tester [12.3K]1 month ago
4 0
The cost is 18.07.
Inessa [12.5K]1 month ago
3 0
For 17 wings, the cost is $17.
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John needs 13 bottles of water from the store. john can only carry 3 at a time. what's the minimum number of trips john needs to
Inessa [12570]
The smallest number of trips he must make is 5. Since he can carry only 3 bottles per trip, 5 trips would allow him to transport 15 bottles.
Though it might seem like 4 trips could suffice, as 4 times 3 is 12, that's one bottle short of 13.
Hence, an additional trip is needed to carry the last bottle, totaling 5 trips.
4 0
3 months ago
A bag holds 12 red marbles, 11 green marbles, 17 blue marbles, and 5 yellow marbles. What is the probability that you will not c
Zina [12379]

¡Hola! Bienvenido a!

Vamos a sumar cuántas canicas tenemos en total.

12+11+17+5=45

Queremos hallar la probabilidad de elegir una canica que no sea azul. Observemos cuántas canicas no son azules.

12+11+5=28

Tendremos esta probabilidad sobre 48.

28/48

Al simplificar, obtenemos 7/12 o alrededor de 58.33%.

¡Espero que esto ayude!

7 0
2 months ago
Read 2 more answers
The Insure.com website reports that the mean annual premium for automobile insurance in the United States was $1,503 in March 20
PIT_PIT [12445]

Answer:

a) Null and alternative hypothesis

H_0: \mu=1503\\\\H_a:\mu< 1503

b) Point estimate d = -$78

c) Test statistic t = -2.438

P-value = 0.0113

Reject H0. This indicates that the average automobile premium in Pennsylvania is lower than in the nation.

Step-by-step breakdown:

This is a statistical test for the average population mean.

The hypothesis posits that car insurance in Pennsylvania is notably less expensive compared to the national average.

Accordingly, the null and alternative hypotheses are:

H_0: \mu=1503\\\\H_a:\mu< 1503

The significance level is set at 0.05.

The sample size is n=25.

The sample mean equates to M=1425.

A point estimate of the difference between the Pennsylvania mean premium and the national average can be computed using the sample mean:

d=M-\mu=1425-1503=-78

Given that the standard deviation of the population is unknown, we approximate it using the sample standard deviation, which is s=160.

The estimated standard error of the mean is determined with the formula:

s_M=\dfrac{s}{\sqrt{n}}=\dfrac{160}{\sqrt{25}}=32

Then, we can calculate the t-statistic as:

t=\dfrac{M-\mu}{s/\sqrt{n}}=\dfrac{1425-1503}{32}=\dfrac{-78}{32}=-2.438

The degrees of freedom for this sample size stand at:

df=n-1=25-1=24

This constitutes a left-tailed test, with 24 degrees of freedom and t=-2.438, rendering the P-value as (per a t-table):

\text{P-value}=P(t

As the P-value (0.0113) falls below the significance level (0.05), the results prove significant.

Thus, the null hypothesis obtains dismissal.

At a 0.05 significance level, there's sufficient evidence to assert that car insurance in Pennsylvania costs notably less than the national average.

8 0
2 months ago
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