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ki77a
16 days ago
11

Timothy built a base for a circular tabletop. The base can support a tabletop with a radius of at least 6 inches, but not more t

han 23 inches. What is the smallest possible area of the tabletop that will fit on Timothy’s table base? Round the answer to the nearest whole square inch. What is the largest possible area of the tabletop that will fit on Timothy’s table base? Round the answer to the nearest whole square inch.
Mathematics
1 answer:
zzz [9K]16 days ago
6 0

Answer:

  • The minimum area for the tabletop is 113 in²

  • The maximum area for the tabletop is 1,662 in²

Explanation:

1) What is the least area required for a tabletop that fits Timothy’s base?

The requirement that the base can accommodate a tabletop with a radius of at least 6 inches indicates that the smallest permissible radius is 6 inches.

a) Area of a circle is calculated as: A = π r²

The smallest area is determined by this minimum radius of 6 in.

b) Calculations:

Thus, A = π (6 in)² = 36π in² ≈ 113.10 in².

Rounding to the nearest whole square inch gives: 113 in²

2) What is the maximum area permitted for a tabletop on Timothy’s base?

The fact that the base can support a tabletop with a maximum radius of 23 inches indicates that the largest allowable radius is 23 inches.

a) Area of a circle is given by: A = π r²

The largest area corresponds to a radius of 23 in, as mentioned above.

b) Calculations:

Therefore, A = π (23 in)² = 529 π in² ≈ 1,661.9 in².

Rounding this result yields: 1,662 in².

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