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SVETLANKA909090
1 month ago
12

(a) Suppose one house from the city will be selected at random. Use the histogram to estimate the probability that the selected

house is valued at less than $500,000. Show your work.
(b) Suppose a random sample of 40 houses are selected from the city. Estimate the probability that the mean value of the 40 houses is less than $500,000. Show your work.

Mathematics
1 answer:
tester [12.3K]1 month ago
3 0

Answer:

a.   0.71

b.   0.9863

Step-by-step explanation:

a. The average of the distribution is specified as $403,000 with a standard deviation of $278,000.

-To calculate the probability of a randomly selected house having a value under $500,000:

P(X

Consequently, the probability that a randomly chosen house is valued at less than $500,000 is 0.71

b. -because 40 is greater than or equal to 30, we assume a normal distribution.

-As such, the probability can be computed as:

P(\bar X)=P(z

Thus, the likelihood that the average value of the 40 selected houses is below $500,000 is 0.9863

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You are visiting a rainforest, but unfortunately,your insect repellent has run out. As a result, at each second, a mosquito land
tester [12383]

Answer:

Step-by-step explanation:

The probability that a mosquito lands on your neck per second is 0.5

The chance of it biting once it lands is 0.2

The likelihood that it does not bite after landing is 0.8

Therefore, the probability of a bite in one second is 0.5(0.2) = 0.01

This translates to a 1/100 likelihood of being bitten in just one second

Over the course of 100 seconds, the expected number of bites is =1

The anticipated interval between bites is 100

6 0
3 months ago
A music buff wants to estimate the percentage of students at a midwestern university who believe that elvis is still alive. how
Leona [12618]
Lacking information on the proportion, we will assume the sample proportion is 0.50

thus,
p = 0.50
The margin of error is set at 10 percentage points. This indicates that the error on either side of the population proportion is 5%, so E = 0.05
z = 1.645 (Z value for a confidence level of 90%)

The calculation for the margin of error when estimating population proportions follows:

E=z* \sqrt{ \frac{p(1-p)}{n} } \\ \\ 
 \frac{E}{z} = \sqrt{ \frac{p(1-p)}{n} } \\ \\ 
( \frac{E}{z} )^{2}= \frac{p(1-p)}{n} \\ \\ 
n= p(1-p)* (\frac{z}{E})^{2} \\ \\ 
n=271

Consequently, 271 students need to be part of the sample.
5 0
2 months ago
Helena has taken out a $9,300 unsubsidized Stafford loan to pay for her college education. She plans to graduate in four years.
Leona [12618]
The effective annual interest rate calculations yield:
i = (1 + 0.064/12)^12 - 1 = 0.066
For year 1: the interest amounts to $613.80 (calculating $9300 multiplied by 0.066)
For year 2: the interest totals $654.31 (adding year 1’s interest to $9300 and multiplying by 0.066)
For year 3: the interest is $656.98 (following the same process as year 2)
For year 4: the interest is $657.16

The cumulative interest totals: $2582.25
The present value of this sum is:
P = 2582.23 / (1 + 0.066)^4 = $1999.72

Thus, the final answer is $1999.72.
8 0
2 months ago
Read 2 more answers
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