John's average for making free throws in a basketball game is .80. In a one-and-one free throw situation (where he shoots a seco
2 answers:
You might be interested in
When two straight lines cross, the vertically opposite angles created are equal, and the remaining two angles match each other as well. Suppose one known angle is x; then the two adjacent angles can be calculated by subtracting twice x from 360 degrees and dividing the remainder by 2.
Thus, the table fills out as follows:
Row 1:
Given angle <GEF = 120°
Angle <FEM is adjacent to <GEF, so
Angle <MEH is vertically opposite to <GEF, making it equal to 120°
Angle <HEG is vertically opposite <FEM, so it equals 60°.
Row 2:
Given angle <MEH = 150°
Since <MEH is vertically opposite to <GEF, <GEF = 150°
Angle <FEM is adjacent to <GEF, thus
Angle <HEG is vertically opposite to <FEM, so <HEG = 30°.
Row 3:
Given angle <FEM = 25°
Angle <FEM is adjacent to <GEF, thus
Angle <MEH is vertically opposite to <GEF, equal to 155°
Angle <HEG is vertically opposite <FEM, so it equals 25°.
Row 4:
Given angle <HEG = 45°
Angle <HEG is adjacent to <GEF, so
Angle <FEM is vertically opposite to <HEG and thus equals 45°
Angle <MEH is vertically opposite to <GEF, hence <MEH = 135°.
Thus, the table fills out as follows:
Row 1:
Given angle <GEF = 120°
Angle <FEM is adjacent to <GEF, so
Angle <MEH is vertically opposite to <GEF, making it equal to 120°
Angle <HEG is vertically opposite <FEM, so it equals 60°.
Row 2:
Given angle <MEH = 150°
Since <MEH is vertically opposite to <GEF, <GEF = 150°
Angle <FEM is adjacent to <GEF, thus
Angle <HEG is vertically opposite to <FEM, so <HEG = 30°.
Row 3:
Given angle <FEM = 25°
Angle <FEM is adjacent to <GEF, thus
Angle <MEH is vertically opposite to <GEF, equal to 155°
Angle <HEG is vertically opposite <FEM, so it equals 25°.
Row 4:
Given angle <HEG = 45°
Angle <HEG is adjacent to <GEF, so
Angle <FEM is vertically opposite to <HEG and thus equals 45°
Angle <MEH is vertically opposite to <GEF, hence <MEH = 135°.
Answer:
a. P(x = 3) = 0.061313
b. The anticipated number of radio blackouts = 4
c. It's unclear when the next radio blackout will occur.
d. P(x = 4) = 0.19537
Step-by-step explanation:
Based on the provided details:
A Poisson process is utilized to model the occurrence of this event:
Minor radio blackouts occur, on average, two times annually.
Therefore:
For question (a)
time t = 1/2 (i.e., six months)
Let x represent the likelihood of 3 incidents during the remaining months of the year.
Then:
P(x = 3) = 0.061313
b).
The expected number of radio blackouts over two years is calculated as follows:
We start with:
t = 2 years
E(x) = λ × t
E(x) = 2 × 2
E(x) = 4
Thus, the predicted number of radio blackouts = 4
c).
The time we must wait until the probability of witnessing the next radio blackout reaches at least 0.5 is as follows:
In this case, time (t) =???
Thus:
P(x =1) = 0.5
Consequently, we are unable to ascertain the probability (50%) of the next radio blackout.
d)
We can compute the probability that the time until the fourth blackout is at most 2 years as follows:
Here;
x =4, t = 2
Thus:
P(x = 4) = 0.19537