Answer:
Step-by-step explanation:
Assuming a fair die is rolled.
- The sample space comprises 1, 2, 3, 4, 5, 6, with all results being equally probable.
Let X represent the collection of all outcomes. Let A represent a specific outcome.
<pThus, the probability of event A occurring is:
Considering that the set of all possible outcomes for a singular die roll is:
Notably,
Here,
since 8 is not included in the sample space. Therefore, rolling an 8 is impossible within the defined outcomes.
<pThis leads to the conclusion that the probability is zero.
In other terms,
<pAs a result,
To solve this problem, you'll want to substitute the first equation into the second or the other way around. The equations given are: 1. 3 paperback books + 5 hardcover books = $80.10; 2. 7 paperback books + 4 hardcover books = $100.65. It is helpful to rearrange the first equation to find 5 hardcover books = $80.10 - 3 paperback books, leading to hardcover book = $16.02 - 0.6 paperback books. Now, substitute this into the second equation: 7 paperback books + 4 ($16.02 - 0.6 paperback books) = $100.65, which simplifies to 7 paperback books + $64.08 - 2.4 paperback books = $100.65. This results in 4.6 paperback books = $100.65 - $64.08 = $36.57, thus paperback book = $7.95. You can then use this price in the first equation to determine the hardcover book price: 3 paperback books + 5 hardcover books = $80.10, substituting gives 3($7.95) + 5 hardcover books = $80.10, which leads to 5 hardcover books = $80.10 - $23.85 = $56.25, therefore hardcover book = $11.25. Hence, the total cost for one paperback and one hardcover book is $7.95 + $11.25 = $19.20.
Answer:
in steps
Step-by-step explanation:
In a fair roulette game, the likelihood of the ball landing on RED remains constant, regardless of prior spins.
a) 18/38
b) 18/38
c) Yes, I have confidence in my responses. Since it's fair, the number of RED slots does not change.
