Mia is attending a team meeting to discuss how to prevent accidents. One of her teammates suggests pushing all the desks against

Answer:

count = 0

while count!= 8:

height = float(input("Enter the height of the rider: "))

if height >= 140:

print("You may ride")

count += 1

else:

if height >= 120:

answer = input("Is the rider accompanied by an adult (yes/no): ")

if answer == "yes":

print("You may ride")

count += 1

else:

print("You are not permitted to ride")

else:

print("You are not permitted to ride")

Explanation:

Begin with a count of zero, which will track the number of riders allowed. Use a while loop that continues until the count reaches 8. During each iteration, request the user's height. If the height is 140 cm or taller, display "You may ride" and increment the count. If the height is 120 cm or more, check if the rider is with an adult. If not, show the message "You are not permitted to ride"; otherwise, allow the ride and increase the count. If the height is below 120 cm, deny the ride.

Answer:

Explanation:

When removing items from a dictionary, always specify the key in quotation marks.

For example: del country_capital['Prussia']

Failing to place it in quotes will cause the interpreter to view Prussia as a variable, resulting in an error saying that Prussia is not defined.

Code:

user_input=input("") #taking input from user

entries=user_input.split(',')    

country_capital=dict(pair.split(':') for pair in entries) #creating the dictionary from user input

del country_capital['Prussia'] #removing Prussia; failure to include quotes results in an error

print('Prussia deleted?', end=' ')

if 'Prussia' in country_capital: #verifying the presence of Prussia in the dictionary

print('No.')

else:

print('Yes.')

print ('Spain deleted?', end=' ')    

if 'Spain' in country_capital: #checking if Spain is present in the dictionary

print('No.')

else:

print('Yes.')

print ('Togo deleted?', end=' ') #verifying the existence of Togo in country_capital

if 'Togo' in country_capital:

print('No.')

else:

print('Yes.')

Explanation:

Answer:

a) Transforming each character into its binary equivalent:

73:

The digits are 7 and 3

7 in binary is: 111

3 in binary is: 11

Thus

73: 0_111_0011

Likewise

F4:

F stands for 15 and its binary is: 1111

4 in binary: 100

Consequently

F4:  1_111_0100

E5:

E corresponds to 14 and its binary form is: 1110

5 in binary: 101

Therefore

E5:  1_110_0101

76:

7 in binary: 111

6 in binary: 110

Hence

76:  0_111_0110

E5:

E has a binary representation of: 1110

5 in binary: 101

Consequently

E5:  1_110_0101

4A:

4 in binary: 100

A represents 10

A in binary form: 1010

Therefore

4A:  0_100_1010

EF:

E in binary is: 1110

F in binary is: 1111

Thus

EF: 1_110_1111

62:

6 in binary form: 110

2 in binary form: 10

Therefore

62:  0_110_0010

73:

The digits are 7 and 3

7 in binary is: 111

3 in binary is: 11

Thus

73: 0_111_0011

for 0_1110011: the decimal equivalent is: 115 which translates to s

for 1_1110100:  the decimal equivalent is: 116 which translates to t

for 1_1100101:  the decimal equivalent is: 101 which translates to e

for 0_1110110: the decimal equivalent is:  118 which translates to v

for 1_1100101:  the decimal equivalent is: 101 which translates to e

for 0_1001010: the decimal equivalent is:  74 which translates to j

for 1_1101111: the decimal equivalent is: 111 which translates to o

for 0_1100010:  the decimal equivalent is: 98 which translates to b

for 0_1110011: the decimal equivalent is:  115 which translates to s

Thus the decoded sequence is:  stevejobs

b) The parity being utilized is odd.

for 0_1110011:  There are 5 instances of 1s and the parity is 0 indicating it is odd.

for 1_1110100: There are 4 instances of 1s and the parity is 1 indicating it is odd.

Thus, we count the number of 1s and then verify if the parity is odd or even.

Likewise

for 1_1100101:  the parity is odd

for 0_1110110: the parity is odd

for 1_1100101:  the parity is odd

for 0_1001010: the parity is odd

for 1_1101111: the parity is odd

for 0_1100010: the parity is odd

for 0_1110011: the parity is odd

Therefore, the parity being used is odd.