Rajan had 6000 RS in his bank account on a particular day a week later he deposited 150p RS and next day he had withdraw 1/3rd o

Answer:

Approximately 59 stacked cups.

Step-by-step explanation:

We have the following measurements:

Height of one cup = 12.5 cm,

Height of two cups stacked = 14 cm,

Height of three cups stacked = 15.5 cm,

...and so on.

This situation can be described by an arithmetic sequence,

12.5, 14, 15.5,....

The first term is defined as a = 12.5,

with a common difference of d = 1.5 cm.

Thus, the height of x stacked cups is given by

As per the problem,

h(x) = 200

⇒ 1.5x + 11 = 200

⇒ 1.5x = 189

⇒ x = 59.3333333333 ≈ 59.

Therefore, you will need approximately 59 stacked cups.

Mr. Rowley
16:14

Ms. Rivera
64:60

Upon simplifying 64:60, it becomes 16:15.
64/4 = 16
60/4 = 15

They are not equivalent since Ms. Rivera holds 1 more exit ticket than Mr. Rowley.

Answer:

The mean and center will be nearly identical, while the variability in simulation B will exceed that of simulation A.

Step-by-step explanation:

Solution

In general, the size of the sample significantly influences the distribution.

As a guideline, by quadrupling the sample size, the sampling error typically reduces by half.

Here, simulation B has a sample size that is twice that of simulation A.

Thus, the sampling error related to the mean is affected, and it stands that A does not have a greater value.

However, its sample size is considerable for this context, making them nearly equal.

Additionally, increased trials lead to decreased variability in simulation. A displays lesser variability.

As trial numbers increase, variability in simulation declines, hence A has lesser variability.

Response:28

Detailed calculation:5x28=140

Answer: 39 cm

Step-by-step explanation:

Let's consider the kite as depicted in the image provided, where TW=5 cm, TX=12 cm, and TZ=4 cm.

First, we need to determine the lengths of the unknown sides to calculate the perimeter, assuming that both the top and bottom parts consist of isosceles triangles.

For the upper segment, we will apply the Pythagorean Theorem to triangle TWZ, with TZ measuring 4 cm and TW being 5 cm. Hence, we must calculate WZ:

By isolating :

For the lower segment, we can apply the Pythagorean Theorem to triangle WZX, where WZ=3 cm and ZX=8 cm. We need to find WX:

Now that the lengths of all sides are identified, the perimeter can be calculated:

The closest option to this calculated value is 39 cm.