Answer: 0.1289
Step-by-step explanation:
Given: The proportion of students absent on Mondays at a large university.: 
Sample size: 
Mean: 
Standard deviation = 
Let x represent a binomial variable.
Referencing the standard normal distribution table,
(1)
Z score for normal distribution:-
For x=4
For x=3
Thus, from (1)
Consequently, the likelihood of four students being absent = 
Let the events be defined as follows:
A=Nathan suffers from an allergy
~A=Nathan does not suffer from an allergy
T=Nathan receives a positive test result
~T=Nathan does not receive a positive test result
According to the provided data,
P(A)=0.75 [ probability indicating that Nathan is allergic ]
P(T|A)=0.98 [ probability of obtaining a positive test result if Nathan is allergic to Penicillin]
We aim to calculate the probability that Nathan is both allergic and tests positive
P(T n A)
Using the definition of conditional probability,
P(T|A)=P(T n A)/P(A)
By substituting the known values,
0.98 = P(T n A) / 0.75
We then solve for P(T n A)
P(T n A) = 0.75*0.98 = 0.735
Hope this assists you!!
This scenario relates to binomial probability, where the results can either be a success or a failure. A success indicates that a selected adult possesses a bachelor's degree. Consequently, the success probability, denoted as p, is 20/100 = 0.2. The number of adults in the sample, represented as n, equals 100, and x, the count of successes, is 60. The probability of having more than 60 adults with a bachelor's degree, represented as P(x >60), can be noted internally as P(x < 60) = binomcdf (100, 0.20, 60). The function binompdf would indicate P(x = 60).
Reducing
9x + -31 = 43
Rearranging the components:
-31 + 9x = 43
Finding the solution
-31 + 9x = 43
Isolating the variable 'x'.
Shift all terms with x to one side,
Add '31' to both sides of the equation.
0 + 31 + 9x = 43 + 31
Summing up similar items:
-31 + 31 = 0
0 + 9x = 43 + 31
9x = 43 + 31
Summing similar items:
43 + 31 = 74
9x = 74
Split each side by '9'
x = 8.222222222
Simplifying
x = 8.222222222
Wallet = belt + 31
jacket = 3 · belt
176 = belt + wallet + jacket
176 = belt + (belt + 31) + (3 · belt)
176 = (2 · belt) + 31 + (3 · belt)
176 = (5 · belt) + 31
5 ·belt = 145
belt = 29
