In triangle ABC, AB = 90 in., BC = 80 in., and angle B measures 50°. What is the approximate perimeter of the triangle?
2 answers:
Answer:
The result is Perimeter = 287.3 in
Detailed explanation:
AB = 90 in
BC = 80 in
∠B = 50
Finding the perimeter =?
Process
1.- First, we need to determine AC using the Law of Sines
A = 42.9 ≈ 43
The sum of angles in a triangle is 180°
A + B + C = 180°
43 + B + 50 = 180
B = 180 - 43 - 50
B = 87°
AC = 117.3
2.- Calculate the perimeter
Perimeter = AB + BC + AC
Perimeter = 90 + 80 + 117.3
Perimeter = 287.3 in
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Solution:
We know, g(x) = f(x) + k --------(1)
It is given that f(x) = (x+2)
and g(x) = (x+5)
Substituting f(x) and g(x) into equation (1):
→ (x+5) =
(x+2) + k
→ = k
→ k =
Thus, the value of k is 1.