The distance between city A and city B is 22 miles. The distance between city B and city C is 54 miles. The distance between cit

Question

14 days ago

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The distance between city A and city B is 22 miles. The distance between city B and city C is 54 miles. The distance between cit

y A and city C is 51 miles.
What type of triangle is created by the three cities?

an acute triangle, because 222 + 542 >512
an acute triangle, because 222 + 512 >542
an obtuse triangle, because 222 + 542 >512
an obtuse triangle, because 222 + 512 >542

Mathematics

2 answers:

AnnZ [9K] · Answer 1 · 2026-03-13T20:04:21+03:00

54 is identified as the hypotenuse since it is the longest side. To analyze the sides, square them all: thus 54^2=2916, 51^2=2601, and 22^2=484. From this, we deduce that 2916=2601+484. When adding those two results, they exceed 2916. Thus, we can conclude that an acute triangle is formed since 22^2+51^2>54^2. Therefore, the answer is B.

PIT_PIT [9.1K] · Answer 2 · 2026-03-13T20:04:25+03:00

The conclusion is that it forms an acute triangle, as 22^2 + 51^2 > 54^2. To determine whether a triangle is categorized as acute or obtuse, the lengths of all sides must be squared. If the square of the largest side is less than the sum of the squares of the two shorter sides, the triangle is acute. Conversely, if the square of the longest side is greater, it results in an obtuse triangle.