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Stella
2 months ago
5

tions - Part 1 A relation is plotted as a linear function on the coordinate plane starting at point E (0, 27)(0, 27) and ending

at point F (5,−8)(5,−8) . What is the rate of change for the linear function and what is its initial value? Select from the drop-down menus to correctly complete the statements. The rate of change for the linear function is and the initial value is
Mathematics
2 answers:
Svet_ta [12.7K]2 months ago
7 0

Answer:

The rate of change is -7 and the initial value is 27

Detailed explanation:


PIT_PIT [12.4K]2 months ago
4 0
We are given the points
<span>E (0, 27)
</span><span>F (5,−8)

and we need to calculate the rate of change and the initial value:

To determine the rate of change, we will apply the slope formula:
m = (-8 - 27) / (5 - 0) = -7
Thus, the rate of change is -7

The initial value refers to the y-coordinate when x equals 0, which corresponds to point E. Therefore, the initial value is 27.</span>
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P(volleyball and baseball) = 4/200 x 100 = 2%
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Thus, 25% of students participate in either volleyball or baseball.
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1 month ago
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Statistics can help decide the authorship of literary works. Sonnets by a certain Elizabethan poet are known to contain an avera
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Response:

It is inferred that the authors of the sonnets belong to a certain poet from the Elizabethan era.

Step-by-step breakdown:

The details provided in the question are as follows:

Population mean, μ = 8.9

Sample mean, \bar{x} = 10.2

Sample size, n = 6

Alpha, α = 0.05

Population standard deviation, σ = 2.5

Initially, we formulate the null hypothesis and the alternative hypothesis

To conduct this test, we utilize the One-tailed z test.

a) Equation:

z_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{\sigma}{\sqrt{n}} }

By substituting in all relevant values, we determine:

z_{stat} = \displaystyle\frac{10.2 - 8.9}{\frac{2.5}{\sqrt{6}} } = 1.28

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b) The p-value is computed using the z-table.

P-value = 0.1003

The p-value surpasses the alpha of 0.05

c) Because the p-value exceeds the alpha threshold, there is insufficient evidence to dismiss the null hypothesis, thereby supporting the null hypothesis.

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Answer:

[[IMG_1]]

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The weight of an orangutan is 64.5 kilograms

Solution:

It is stated that the orangutan's weight is 142 pounds

Additionally,

1 kilogram is approximately 2.2 pounds

We will now convert 142 pounds into kilograms

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As a result, 142 pounds translates to

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When rounding to the nearest tenth, we obtain 64.5 kilograms

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