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Strike441
8 days ago
13

Which of the following scenarios best describes division of a polynomial using synthetic division? Select all that apply. The di

vision must occur between a polynomial and a linear term. Synthetic division uses only the variables when finding the quotient. If there is a number in the last term of the quotient, then there is a remainder. The quotient is written as a polynomial with a degree one power greater than the original dividend.
Mathematics
1 answer:
Svet_ta [9.5K]8 days ago
7 0

Response:

Synthetic division involves dividing a polynomial exclusively by a linear factor.

Elaboration:

The valid points are:

1. The division must occur involving a polynomial and a linear expression.

3. If the last term in the quotient contains a number, a remainder will exist. After performing the division, if a number other than zero remains in the final term of the quotient, it is classified as the remainder.

4. The resulting quotient is represented as a polynomial with a degree one higher than that of the original dividend.

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The equation of the tangent plane to the ellipsoid x2/a2 + y2/b2 + z2/c2 = 1 at the point (x0, y0, z0) can be written as xx0 a2
PIT_PIT [9121]

Answer:

The tangent plane equation for the hyperboloid

\frac{xx_0}{a^2}+\frac{yy_0}{b^2}-\frac{zz_0}{c^2}=1.

Step-by-step explanation:

We have

The ellipsoid's equation is

\frac{x^2}{a^2}+\frac{y^2}{b^2}+\frac{z^2}{c^2}=1

The equation for the tangent plane at the point \left(x_0,y_0,z_0\right)

\frac{xx_0}{a^2}+\frac{yy_0}{b^2}+\frac{zz_0}{c^2}=1  (Given)

The hyperboloid's equation is

\frac{x^2}{a^2}+\frac{y^2}{b^2}-\frac{z^2}{c^2}=1

F(x,y,z)=\frac{x^2}{a^2}+\frac{y^2}{b^2}-\frac{z^2}[c^2}

F_x=\frac{2x}{a^2},F_y=\frac{2y}{b^2},F_z=-\frac{2z}{c^2}

(F_x,F_y,F_z)(x_0,y_0,z_0)=\left(\frac{2x_0}{a^2},\frac{2y_0}{b^2},-\frac{2z_0}{c^2}\right)

The tangent plane equation at point \left(x_0,y_0,z_0\right)

\frac{2x_0}{a^2}(x-x_0)+\frac{2y_0}{b^2}(y-y_0)-\farc{2z_0}{c^2}(z-z_0)=0

The tangent plane equation for the hyperboloid is

\frac{2xx_0}{a^2}+\frac{2yy_0}{b^2}-\frac{2zz_0}{c^2}-2\left(\frac{x_0^2}{a^2}+\frac{y_0^2}{b^2}-\frac{z_0^2}{c^2}\right)=0

The tangent plane equation

2\left(\frac{xx_0}{a^2}+\frac{yy_0}{b^2}-\frac{zz_0}{c^2}\right)=2

Hence, the required tangent plane equation for the hyperboloid is

\frac{xx_0}{a^2}+\frac{yy_0}{b^2}-\frac{zz_0}{c^2}=0

7 0
1 month ago
Ms. Gallegos burns 236 calories riding her bike each hour. She wants to burn more than 590 calories riding her bike at the same
Svet_ta [9518]

Response:

354

Detailed explanation:

5 0
26 days ago
Find a122 of the sequence 5, 8, 11
Svet_ta [9518]
To find a122 in the sequence beginning with 5, 8, 11, we recognize this series is arithmetic.
8 0
22 days ago
A small plane flies 760,320 yards in 2 hours. Use the formula d = rt, where d represents distance, r represents rate, and t repr
tester [8842]

Answer:

Refer to the explanation below.

Step-by-step explanation:

We start with a small aircraft that flies 760,320 yards within a duration of 2 hours.

A)

The formula for distance is:

d=rt

To isolate the rate r, we divide both sides by time:

r=\frac{d}{t}

B)

To calculate the rate in yards per hour, divide the total yards by the hours taken. Therefore:

r=\frac{\text{760320 yards}}{\text{2 hours}}

Perform division:

r=\text{380160 yd/hr}

Thus, the aircraft speeds at 380,160 yards every hour.

C)

There are 1,760 yards in a mile.

To compute the speed in miles per hour, we apply dimensional analysis.

We recognize the rate is 380,160 yards per hour:

r=\frac{\text{380160 yards}}{\text{1 hour}}

To cancel "yards" from the numerator, we multiply by 1 mi/1,760 yards. Therefore:

r=\frac{\text{380160 yards}}{\text{1 hour}}\cdot \frac{\text{1 mi}}{\text{1760 yards}}

This eliminates yards:

r=\frac{\text{380160}}{\text{1 hour}}\cdot \frac{\text{1 mi}}{\text{1760}}

Now, multiply the values across:

r=\frac{\text{380160 mi}}{\text{1760 hour}}

Then divide:

r=\frac{\text{216 miles}}{\text{ hour}}

The final rate for the plane is 216 miles per hour.

D)

Miles are a more appropriate measurement in this context because the distance is substantial, making it impractical to express using yards. A rate of 380,160 yards per hour is excessive, whereas 216 miles per hour provides a clearer understanding.

7 0
28 days ago
A circle with radius of \greenD{1\,\text{cm}}1cmstart color #1fab54, 1, start text, c, m, end text, end color #1fab54 sits insid
AnnZ [9104]

Response:

8.86cm^2

Detailed breakdown:

Considering a rectangle measuring 3cm by 4cm with a circle of 1 cm diameter within it:

The area of the shaded section equals Area of Rectangle minus Area of Circle

The area of a rectangle is calculated as Length multiplied by Width

=3 X 4 =12cm^2

The area of the circle is \pi r^2=\pi X 1^1=3.142cm^2

Area of shaded region = 12 - 3.142

=8.86cm^2



6 0
2 days ago
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