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Archy
2 months ago
10

An element with mass 730 grams decays by 28.8% per minute. How much of the element is remaining after 10 minutes, to the nearest

10th of a gram?
Mathematics
2 answers:
babunello [11.8K]2 months ago
8 0

Answer:

A = 24.4 grams

Step-by-step explanation:

A substance weighing 730 grams experiences a decay of 28.8% every minute

We apply the formula for exponential decay

A= P(1-r)^t

In this equation, P denotes the initial quantity of the substance

A represents the remaining amount

r indicates the decay percentage

and t signifies the time in minutes

P= 730 grams, r= 28.8% = 28.8/100 = 0.288, t = 10 minutes

A= 730(1-0.288)^10

A = 24.44122

Rounding to the nearest tenth

Thus A = 24.4 grams

AnnZ [12.3K]2 months ago
6 0
\bf \qquad \textit{Amount for Exponential Decay}\\\\
A=P(1 - r)^t\qquad 
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{initial amount}\to &730\\
r=rate\to 28.8\%\to \frac{28.8}{100}\to &0.288\\
t=\textit{elapsed time}\to &10\\
\end{cases}
\\\\\\
A=730(1-0.288)^{10}\implies A=730(0.712)^{10}
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