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ANEK
2 months ago
14

Write a program that prompts the user for an integer, then asks the user to enter that many values. Store these values in an arr

ay and print the array. Then reverse the array elements so that the first element becomes the last element, the second element becomes the second to last element, and so on, with the old last element now first. Do not just reverse the order in which they are printed; actually change the way they are stored in the array. Do not create a second array; just rearrange the elements within the array you have.
Computers and Technology
1 answer:
Rzqust [1K]2 months ago
3 0

Answer:

//To facilitate user input, the Scanner class is imported

import java.util.Scanner;

//The Solution class is being defined

public class Solution {

   //The main method is declared here, marking the start of program execution

   public static void main(String args[]) {

       

       //A Scanner object named 'scan' is instantiated to gather user input

       Scanner scan = new Scanner(System.in);

       //User is prompted to specify the size of the array

       System.out.print("Enter the range of array: ");

       //The user input is stored in arraySize

       int arraySize = scan.nextInt();

       //Initialization of userArray with the size specified by arraySize

       int[] userArray = new int[arraySize];

       

       //A counter is initialized to track the number of elements entered in the array

       int count = 0;

       //The following while loop will continue until the user finishes inputting the elements of the array

       while (count < arraySize){

           System.out.print("Enter each element of the array: ");

           userArray[count] = scan.nextInt();

           count++;

       }

       

       //A blank line is outputted for better readability

       System.out.println();

       

       //A for loop iterates to print all elements of the array in a single line

       for(int i =0; i <userArray.length; i++){

           System.out.print(userArray[i] + " ");

       }

       

       //Another blank line is printed for clarity

       System.out.println();

       

       //A for loop is utilized to reverse the contents of the array

       for(int i=0; i<userArray.length/2; i++){

           int temp = userArray[i];

           userArray[i] = userArray[userArray.length -i -1];

           userArray[userArray.length -i -1] = temp;

       }

       

       //A for loop prints each element of the reversed array in one line

       for(int i =0; i <userArray.length; i++){

           System.out.print(userArray[i] + " ");

       }

     

   }

}

Explanation:

The program is annotated to provide a thorough explanation.

The for-loop responsible for reversing the array operates by splitting the array into two segments and swapping elements from the first segment with those from the second segment. During each loop, an element from the first segment is temporarily stored in temp variable, and then that element is replaced with the corresponding element from the second segment. Subsequently, the element from the second segment is updated with the value held in temp.

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Response:

#code (count_seq.py)

def count_seq():

   n='2'

   while True:

       yield int(n)

       next_value=''

       while len(n)>0:

           first=n[0]

           count=0

     

           while len(n)>0 and n[0]==first:

               count+=1

               n=n[1:]

           next_value+='{}{}'.format(count,first)

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   for i in range(10):

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Clarification:

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  • Repeat as long as n has content and the first digit matches the leading digit.
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Explanation:

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