To obtain a complete response, the diagram would be essential. However, to approximate the solution, I'd calculate the distances from her home to her school and combine that with the stretch from school to work, and finally, from work back home. If there’s no information regarding the distance from work to home, I’d simply double the traveled distance already accounted for.
Regardless of the value of M, it will correspond to 18m squared.
(a) For E based on d, the equation is E = 6500 - 50d
(b) After 30 days, the remaining excess will be 5000.
Answer:
A), B), and C) are clarified below.
Step-by-step explanation:
The inquiry involves using binary digits, employing probabilities that are equal for both conditions, by applying a random test pattern, where the formula is derived from p = q.
Simplifying gives us
P[k] = nCk / 2^n
A. Probability of all bits being 1s
16c16/2^16 = 1/65536
B. Probability of all bits being 0s
16c0/2^16 = 1/65536
C. The probability of having exactly 8 bits as 1s and the other 8 as 0s
16c8/2^16 = 12870/65536 => 0.1963 ≈ 19.63%
Answer:
Step-by-step explanation:
Given
Solving for (a): n
To find n;
We will utilize
Substituting values for XY and XZ
Dividing by -6
Solving for (b) XY
Substituting 3 for n
Solving for (c): XZ
