Thirty-six of the staff of 80 teachers at a local intermediate school are certified in Cardio-Pulmonary Resuscitation (CPR). In
1 answer:
Answer:
In approximately 81 days, it is likely that the teacher on bus duty will be certified in CPR
Step-by-step explanation:
The probability of a teacher obtaining certification in Cardio-Pulmonary Resuscitation (CPR) is as follows:
36 out of 80
Hence
In a school year lasting 180 days, how many days can we anticipate that the teacher on bus duty will likely have CPR certification?
45% of the time
0.45 multiplied by 180 results in 81 days
In approximately 81 days, it is likely that the teacher on bus duty will be certified in CPR
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Answer:
We conclude that less than or equal to 50% of the student body supports him significantly.
Step-by-step explanation:
Mike, while campaigning for the student government presidency, is keen to determine if more than 50% of the student body supports him.
A random sample of 100 students was surveyed, with 55 expressing support for Mike.
Let p = the proportion of students backing Mike.
Thus, Null Hypothesis, : p
50% {indicating that the proportion of supporters among the student body is significantly less than or equal to 50%}
Alternate Hypothesis, : p > 50% {indicating that the proportion of supporters among the student body is significantly more than 50%}
The test statistics to be utilized here One-sample z proportion statistics;
T.S. = ~ N(0,1)
where, = the sampled proportion in favor of Mike =
= 0.55
n = number of sampled students = 100
Therefore, test statistics =
= 1.01
The z test statistic is 1.01.
At a significance level of 0.05, the z table provides a critical value of 1.645 for a right-tailed test.
Given that our test statistic falls below the critical value of z (1.01 < 1.645), we lack sufficient evidence to reject the null hypothesis as it remains outside the rejection region, leading to failure to reject our null hypothesis.
As a result, we conclude that less than or equal to 50% of the student body is in favor of him or the proportion supporting Mike is not significantly greater than 50%.
We apply the slope formula by substituting the given points.
Here, x2 equals 5 and x1 equals -2; y2 equals -3 and y1 equals 6.
Thus, the line's slope is -9 divided by 7.
Answer:
The price amounts to $9.70 per kilogram.
Step-by-step explanation:
This can be resolved using the rule of three.
In a rule of three scenario, the first step involves determining how the values are related, whether directly or inversely.
A direct relationship implies that when one measure increases, the corresponding measure also increases. In this case, cross multiplication serves as the method for the rule of three.
Alternatively, an inverse relationship indicates that an increase in one measurement causes a decrease in the other. In this scenario, line multiplication applies.
Here, the relationship is between the weight of the cheese and its cost. As the weight rises, so does the expense, representing a direct proportion.
Solution:
According to the problem, cheese is priced at $4.40 per pound. Given that each kg equals 2.2 pounds, we can deduce how many kg correspond to one pound.
1 pound - x kg
2.2 pounds - 1 kg
kg
Given that cheese costs $4.40 for a pound, and there are 0.45 kg in one pound, we calculate the cost for 1 kg.
$4.40 - 0.45 kg
$x - 1 kg
The price is $9.70 per kilogram.