Response:
C. Each person receives 1/4 lb of chicken
Step-by-step analysis:
Determine the rate of chicken per person.
A chef prepares 9 lbs of chicken for 36 individuals and 17 lbs for 68 individuals.
A. 9/17 lb per individual
B. 4 lb per individual
C. 1/4 lb per individual
D. 36 individuals
Calculation:
9 lbs for 36 individuals
Chicken per individual = Total chicken / Total number of individuals
= 9 lbs / 36 individuals
Chicken per individual = 1/4 lb of chicken
17 lbs for 68 individuals
Chicken per individual = Total chicken / Total number of individuals
= 17 lbs / 68 individuals
= 1/4 lb each
Consequently, the rate of chicken per individual = 1/4 lb of chicken.
Solution:
[(2x² + 5x) + (4x² – 4x)] + 5x³ =
(2x² + 5x) + [(4x² – 4x) + 5x³]
Step-by-step breakdown:
Answer:
The range of cheerleaders' heights lies within the interval [58, 74)
It includes all real numbers from 58 inches and above, but below 74 inches.
Step-by-step explanation:
we have

Separate the combined inequality into two distinct inequalities
-----> inequality A
-----> inequality B
Solve inequality A

Subtract 28 from both sides

Split by 4 on both sides

Reformulate

Address inequality B

Subtract 28 from both sides

Split by 4 on both sides

consequently
The height range of the cheerleaders is the interval [58, 74)
It consists of every real number starting from 58 inches and less than 74 inches
Answer:
Given that the frog jumps every 10 seconds
(using digits from a random number table)
- It requires 7 jumps with 2 in the reverse direction (either left or right) for the frog to get off the board in 60 seconds.
- Alternatively, 3 jumps in the same direction will also lead to the frog being off the board.
- Furthermore, it would take 5 jumps with one in the opposite direction within the time limit of 60 seconds to leave the board.
Step-by-step explanation:
A frog positioned right at the center of a 5ft long board is 2.5 ft away from either edge.
Every 10 seconds, the frog jumps left or right.
If the frog's jumps are LLRLRL, it will remain on the board at the leftmost square.
If it jumps as LLRLL, it will jump off the board after fifty seconds.
Given that the frog jumps every 10 seconds
(using digits from a random number table)
- It requires 7 jumps with 2 in reverse direction (either left or right) for the frog to get off the board in 60 seconds.
- Alternatively, 3 jumps in the same direction will also lead to the frog being off the board.
- Furthermore, it would take 5 jumps with one in the opposite direction within the time limit of 60 seconds to leave the board.
Step-by-step explanation:
What is a34 of the sequence 9,6,3,..
r=a2-a1
r=6-9
r=-3
a34=a1+33.r
a34=9+33.(-3)
a34= 9-99
a34= -90
hope this helps!
bye!