Discussion Question 10: A bank in California has 13 branches spread throughout northern California , each with its own minicompu

Answer:

count = 0

while count!= 8:

height = float(input("Enter the height of the rider: "))

if height >= 140:

print("You may ride")

count += 1

else:

if height >= 120:

answer = input("Is the rider accompanied by an adult (yes/no): ")

if answer == "yes":

print("You may ride")

count += 1

else:

print("You are not permitted to ride")

else:

print("You are not permitted to ride")

Explanation:

Begin with a count of zero, which will track the number of riders allowed. Use a while loop that continues until the count reaches 8. During each iteration, request the user's height. If the height is 140 cm or taller, display "You may ride" and increment the count. If the height is 120 cm or more, check if the rider is with an adult. If not, show the message "You are not permitted to ride"; otherwise, allow the ride and increase the count. If the height is below 120 cm, deny the ride.

Answer:

1. #include <iostream>

2. #include <cmath>

3.  

4. using namespace std;

5.  

6. int main()

7. {

8.     float radius;  

9.     cout << "Type the radius of the base: "; // Input a number

10.     cin >> radius; // Capture user input

11.      

12.     float height;  

13.     cout << "Type the height: "; // Enter a number and press enter

14.     cin >> height; // Get user input

15.      

16.     float volumeCylinder = 3.1416 * radius * radius * height;

17.     float cubeSide = std::pow(volumeCylinder, 1/3.);

18.     cout<<"Cube side is: "<< cubeSide;

19.      

20.     return cubeSide;

21. }

Explanation:

• Lines 1 to 5 observe two libraries
• Lines 6 to 7 declare the main function
• Lines 8 to 11 solicit the radius of the cylinder from the user
• Lines 12 to 15 request the user to input the cylinder's height
• Line 16 calculates the cylinder's volume with the formula        V=pi*(r^2)*h
• Line 17 computes the side length of a cube with a matching volume as the cylinder using side=∛(V)
• Lines 18 to 21 display and return the cube's side length

Response:

#section 1

def listofWordswitha(text):

   ''' This function outputs all words from a string that include the letter 'a' '''

   tex = text.split()

   new = []

#section 2

   for word in tex:

       for char in word:

           if char == 'a':

               new.append(word)

               break

   return new

Clarification:

#section 1

First, you need to establish your function and provide an argument representing the string that will be utilized.

It's beneficial to include a docstring that describes the function's purpose, which I've added.

Then, use the split method to break the string into a list. In conclusion, you create a list to store all the words that contain 'a'.

#section 2

The terminology chosen is specific to facilitate understanding.

FOR EVERY WORD inside the list and FOR EACH LETTER in the WORD.

IF a LETTER 'a' is found in the word, ADD that WORD to the NEW LIST.

The append function serves to incorporate new entries into the list.

A break statement is employed to avoid redundancy since some words might have multiple instances of 'a'. Thus, upon encountering a word containing 'a', it appends it and shifts to the next word.

Ultimately, the new list is returned.

I will utilize your inquiry to validate the code and provide the results for you.