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devlian
2 months ago
12

Henry works at a warehouse where he earns $23.56 per hour. How much money will Henry earn after working for 37 hours and 42 minu

tes
Mathematics
1 answer:
babunello [11.8K]2 months ago
8 0

Response:

$888.21

Detailed explanation:

We'll split this problem into two parts.

First, determine how much money Henry earns after working for 37 hours. He makes $23.56 an hour, thus you multiply his worked hours (37) by his hourly rate (23.56) which results in $871.72.

Next, you need to account for the additional 42 minutes after the 37 hours. Since there are 60 minutes in an hour, you convert 42 minutes to hours by dividing by 60, giving you 0.7. Multiply 0.7 by $23.56 (his hourly rate) to obtain $16.49.

Combining both sums gives a total of 888.21 dollars.

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2. Santiago wants the lateral surfaces of the
Inessa [12570]

Answer:

Red paint will cover 262 square feet

of the ramp.

Step-by-step explanation:

The lateral surface area represents the surface area of the sides of the ramp without including the top and bottom surfaces

This ramp has three surfaces

The two sides are triangular with dimensions of length 20 and height 8.5

The back consists of a rectangular shape with length 12 and height 8.5

Step 1: Calculating the Area of Triangle

The area of the triangular side = \frac{1}{2} length \times height

The area of the triangle = \frac{1}{2} (20 \times 8.5)

The area of the triangle = \frac{170}{2}    

Thus, the area of the triangle = 85 square feet

Area of both triangles = 85 \times 2  =  170

Step 2: Finding the Area of Rectangle

Area of rectangle = length \times height

therefore,

Area of the rectangular back = 12 \times 8.5 = 102  square feet

Step 3: Calculating the total lateral surface area

Overall Lateral Surface Area

= Area of triangles + Area of Rectangle

= 272 square feet

8 0
2 months ago
The savings account offering which of these APRs and compounding periods offers the best APY?
zzz [12365]
\bf \qquad \qquad \textit{Annual Yield Formula}
\\\\
~~~~~~~~~~~~\textit{4.0784\% compounded monthly}\\\\
~~~~~~~~~~~~\left(1+\frac{r}{n}\right)^{n}-1
\\\\
\begin{cases}
r=rate\to 4.0784\%\to \frac{4.0784}{100}\to &0.040784\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{monthly, thus twelve}
\end{array}\to &12
\end{cases}
\\\\\\
\left(1+\frac{0.040784}{12}\right)^{12}-1\\\\
-------------------------------\\\\
~~~~~~~~~~~~\textit{4.0798\% compounded semiannually}\\\\


\bf ~~~~~~~~~~~~\left(1+\frac{r}{n}\right)^{n}-1
\\\\
\begin{cases}
r=rate\to 4.0798\%\to \frac{4.0798}{100}\to &0.040798\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{semi-annually, thus twice}
\end{array}\to &2
\end{cases}
\\\\\\
\left(1+\frac{0.040798}{2}\right)^{2}-1\\\\
-------------------------------\\\\


\bf ~~~~~~~~~~~~\textit{4.0730\% compounded daily}\\\\
~~~~~~~~~~~~\left(1+\frac{r}{n}\right)^{n}-1
\\\\
\begin{cases}
r=rate\to 4.0730\%\to \frac{4.0730}{100}\to &0.040730\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{daily, thus 365}
\end{array}\to &365
\end{cases}
\\\\\\
\left(1+\frac{0.040730}{365}\right)^{365}-1
7 0
2 months ago
Read 2 more answers
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