Honestly, I find Mrs. Garcia's method easier to perform mentally. It hinges on how familiar you are with your multiples of 5. (5*15 = 75 is a multiplication I often use)
Melissa's approach involves calculating 5*20 = 100 and 5*9 = 45, then combines the 3-digit result 100 with the 2-digit result 45, yielding 145. Adding 45 to 00 is simple and doesn’t require carrying digits, thus the arithmetic is fairly straightforward.
Mrs. Garcia's technique involves computing 5*14 = 70 and 5*15 = 75, then summing these two-digit results. Many people may not readily recall that 5*15=75, which complicates forming that product. The addition of 70 and 75 requires a carrying operation, making the math somewhat more complex. The resulting total is 145.
(The rationale behind my preference for Mrs. Garcia's method is that I can achieve the final sum by simply doubling 7 tens, followed by adding 5. The only 3-digit number to remember mentally is the ultimate total.)
_____Subtraction introduces a slight complication, yet reshaping it as $5(30 -1) = $150 - 5 = $145 is possible.
Or, you may reframe it as $5(28 +1) = $140 +5 = $145.
Dividing an even number by 2 to find the product of 5 is straightforward when you append a zero.
5*14 = 10*7 = 70
5*28 = 10*14 = 140.
Answer:
13.8%
Step-by-step explanation:
With six employees and six checks, there are a total of 36 (6x6) possible distributions. To determine the probability that exactly five individuals receive the correct checks, there’s only one correct distribution for each of them out of the 36 possibilities, resulting in the calculation of 1/36 for the first and then 1/36 for the subsequent checks. Therefore, the final probability becomes 5/36 = 13.8%.
Hello!
Before you tackle any problems, it's essential to designate which scenario represents event A and which corresponds to event B. I usually follow the order they are presented in the question, so:
A = S<span>tudent participates in student council
B = S</span><span>tudent participates in after school sports
Any problem that mentions "given" in the question will need to refer to </span>P(A | B)<span> = P(</span>A ∩ B)/P(B). P(A | B) essentially represents the "probability of event A, given that event B has occurred." Meanwhile, P(A ∩ B) denotes the likelihood of both A and B taking place, while P(B) signifies just the probability of event B happening. All required information has been provided, so:
P(A | B) = P(A ∩ B)/P(B)
P(A | B) = 11% / 62%
P(A | B) = 0.11 / 0.62
P(A | B) = 0.18
Thus, there is approximately an 18% probability that <span>a student is involved in student council, given participation in after school sports.
I hope this was helpful!:-)</span>
Answer:
150
Step-by-step explanation:
We perform addition.
a) The total of 48 added to itself
= 48 + 48 = 96
b) Its half plus half of the half
= 96 + (1/2 × 48) + (1/2 × (1/2 × 48)
= 96 + 24 + (1/2 × 24)
= 96 + 24 + 12
= 132
c) plus 18
= 132 + 18
= 150
Thus, adding 48 to itself, its half, and half of that to 18 results in 150.
