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Lisa
1 month ago
10

c++ 2.30 LAB: Phone number breakdown Given a long long integer representing a 10-digit phone number, output the area code, prefi

x, and line number, separated by hyphens. Ex: If the input is: 8005551212 the output is: 800-555-1212 Hint: Use % to get the desired rightmost digits. Ex: The rightmost 2 digits of 572 is gotten by 572 % 100, which is 72. Hint: Use / to shift right by the desired amount. Ex: Shifting 572 right by 2 digits is done by 572 / 100, which yields 5. (Recall integer division discards the fraction). For simplicity, assume any part starts with a non-zero digit. So 999-011-9999 is not allowed. LAB
Computers and Technology
1 answer:
oksian1 [804]1 month ago
5 0

Answer:

#include <iostream>

using namespace std;

int main()

{

   // Declare variables to hold entire phone number and its components

   long phone_number;

   int area_code, prefix, line_number;

   cout << "Enter 10-digit phone number:" << endl;

   // Take 10-digit phone number input

   cin >> phone_number;

   // Extract area code, prefix, and line number

   area_code = phone_number / 10000000;

   prefix = (phone_number / 10000) % 1000;

   line_number = phone_number % 10000;

   // Output phone number in desired hyphen-separated format

   cout << area_code << "-" << prefix << "-" << line_number << endl;

   return 0;

}

Output:

Enter 10-digit phone number:

8005551212

800-555-1212

Explanation:

The program takes a 10-digit phone number input from the user and stores it in the variable phone_number.

Using division and modulus operations, it separates the phone number into three parts:

area_code = phone_number / 10000000;

prefix = (phone_number / 10000) % 1000;

line_number = phone_number % 10000;

Finally, the program prints these parts joined by hyphens.

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