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liubo4ka
2 months ago
14

Consider the continuous random variable X, which has a uniform distribution over the interval from 20 to 28.

Mathematics
1 answer:
PIT_PIT [12.4K]2 months ago
4 0
a) The specified probability distribution is b) 0.5, representing a 50% chance that X assumes a value between 21 and 25. c) 0.25 denotes a 25% likelihood that X takes on a value of at least 26. A uniform probability distribution encompasses two limits, a and b. The probability of obtaining a value lower than x is calculated accordingly. Also, the likelihood of finding a value between c and d is defined in correlation with the observed uniform distribution ranging from 20 to 28.
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The sequence 6, 18, 54, 162, … shows the number of pushups Kendall did each week, starting
Svet_ta [12734]

a) The sequence is geometric.

b) The subsequent term is 486

c) The rule is: a_n=6(3)^{n-1}

The 20th term will be: a_{20}=6973568802

Step-by-step explanation:

The series 6, 18, 54, 162, ... depicts the number of push-ups Kendall performed each week, starting from her initial week of exercise.

Part a) Is this sequence arithmetic or geometric?

An arithmetic sequence has a constant difference between consecutive terms.

In the given series 6, 18, 54, 162,

18-6 = 12

54-18= 36

The differences are not constant, thus it isn’t arithmetic.

A geometric sequence maintains a constant ratio between consecutive terms.

In this series 6, 18, 54, 162,

18/6 = 3

54/18 = 3

162/54 = 3

The ratios remain constant; therefore, the sequence is geometric.

The sequence in question is geometric.

Part b) How can you determine the next number in the series?

The next number can be calculated using the following formula:

a_n=a(r)^{n-1}

where a_n= nth term

a= first term

r= common ratio

The next number represents the 5th term of the sequence.

To find the 5th term:

a_n=a(r)^{n-1}\\a_5=6(3)^{5-1}\\a_5=6(3)^4\\a_5=6*81\\a_5=486

Thus, the next term in the sequence is 486

Part c) What is the rule for determining the 20th week? Calculate the 20th week.

The rule for determining the 20th week is:

a_n=6(3)^{n-1}

Here n=20

Calculating the 20th week

a_n=6(3)^{n-1}\\a_{20}=6(3)^{20-1}\\a_(20)=6(3)^{19}\\a_{20}=6973568802

5 0
3 months ago
The height h and collar size c , both in centimeters, measured from a sample of boys were used to create the regression line cˆ=
zzz [12365]

Response:

This is the C=intercept of the regression line

Step-by-step clarification:

The regression line's slope is logically interpreted as the average increase in collar size for each 1cm increment in height.

6 0
1 month ago
Find the midpoint of the segment with endpoints of −11 + i and −4 + 4i.
tester [12383]

\bf \begin{cases} -11+i\implies -11+1i\\ \qquad (-11,1)\\ -4+4i\\ \qquad (-4,4) \end{cases} \\\\\\ ~~~~~~~~~~~~\textit{middle point of 2 points } \\\\ (\stackrel{x_1}{-11}~,~\stackrel{y_1}{1})\qquad (\stackrel{x_2}{-4}~,~\stackrel{y_2}{4}) \qquad \left(\cfrac{ x_2 + x_1}{2}~~~,~~~ \cfrac{ y_2 + y_1}{2} \right)


\bf \left( \cfrac{-4-11}{2}~~,~~ \cfrac{4+1}{2}\right)\implies \left(-\frac{15}{2}~,~\frac{5}{2} \right)\implies \left(-7\frac{1}{2}~,~2\frac{1}{2} \right) \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ ~\hfill -7\frac{1}{2}+2\frac{1}{2}i~\hfill

5 0
2 months ago
Read 2 more answers
A set of face cards contains 4 Jacks, 4 Queens, and 4 Kings. Carlie chooses a card from the set, records the type of card, and t
PIT_PIT [12445]
<span>The accurate answer is "<span>The experimental probability is 1/15 lower than the theoretical probability."

The attached table illustrated in the image indicates that the theoretical probabilities are: 2/5 for drawing a Jack, 4/15 for a Queen, and 1/3 for a King, based on the frequency of each card in the set.
</span>
</span>
8 0
3 months ago
Read 2 more answers
Manufacture of a certain component requires three different machining operations. Machining time for each operation has a normal
PIT_PIT [12445]

Answer:

0.0359

Step-by-step explanation:

Provided values:

Mean durations of three independent processes are 15, 30, and 20 minutes.

The associated standard deviations are 2, 1, and 1.6 minutes, respectively.

Thus,

New Mean = 15 + 30 + 25 = 65

Variance = (standard deviation)²

or

Variance = 2² + 1² + 1.6² = 7.56

<phence>

Standard deviation = √variance

or

Standard deviation = 2.75

<pas a="" result="">

Z-value = \frac{\textup{60 - 65}}{\textup{2.75}}

or

Z-value = - 1.81

Consulting the Z-table, the Probability of Z ≤ -1.81 is equal to 0.0359.

</pas></phence>
6 0
2 months ago
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