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asambeis
2 days ago
13

The Florida Tourist Commission selected a random sample of 200 people that attended one or more concerts during the first weeken

d in April of 2010. The survey revealed that 120 concert goers went to Orlampa Skydome and 100 went to the Bithlo Megaplax. Calculate the probability that a selected concert goer during the same weekend next year will go to either the Orlampa Skydome OR the Bithlo Megaplax?
Mathematics
1 answer:
Inessa [12.1K]2 days ago
6 0

Answer:

0.8 or 80%

Step-by-step explanation:

Let A and B denote the different events

A: “The concert attendee visited Orlampa Skydome”

B: “The concert attendee visited the Bithlo Megaplax”

Thus, the probability P(A) of a concert attendee visiting Orlampa Skydome is

P(A) = 120/200 = 0.6

In a similar manner,

P(B) = 100/200 = 0.5

We seek to determine P(A∪B), which represents the odds that a concert attendee went to either Orlampa Skydome OR the Bithlo Megaplax.

We know that

P(A∪B) = P(A) + P(B) - P(A∩B)

but P(A∩B) signifies the possibility that a concert attendee went to both Orlampa Skydome AND the Bithlo Megaplax.

Given that the events are independent,  

P(A∩B) = P(A)P(B) = 0.6*0.5 = 0.3

and

P(A∪B) = 0.6 +0.5 - 0.3 = 0.8 or 80%

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Wyjaśnienie krok po kroku:

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Użyj mnożników Lagrange'a, mamy

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\frac{y}{x} =\frac{x}{y} \\x^2=y^2

Podobnie y^2=z^2

Zatem otrzymujemy 3x^2 =1\\x = \frac{1}{\sqrt{3} }

Stąd wymiary to

(2x,2y,2z)

<pzatem wymiary="" to="">

\frac{2}{\sqrt{3} },\frac{2}{\sqrt{3} },\frac{2}{\sqrt{3} } )

</pzatem>
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