The house Trevor's family lives in has 6 66 people (including Trevor) and 3 33 bathrooms. In the past month, each person showere

Response:

b

Detailed explanation:

Answer:

I believe it takes 4 hours

Step-by-step explanation:

8400m ÷ 35m = 240 mins

240 mins = 4 hours

The formula for gravitational force is F = G * m1 * m2 / r². The gravitational constant is G = 6.67 * 10^(-11) m³/kgs². Thus, we find r = sqrt(G * m1 * m2 / F) = sqrt(6.67 * 10^(-11) m³/kgs² * 1.3 * 10^(22) kg * 1.6 * 10^(21) / 3.61 * 10^(18) N) = sqrt(3.84 * 10^(14)) = 1.96 * 10^(7) m, which is approximately 2 * 10^(7) m.

Answer:

1. Addition Property of Equality

2. Segment addition

3. Substitution Property of Equality.

4. Transitive Property of Equality.

Step-by-step explanation:

Given: CD = EF and AB = CE

To Show: AB = DF

Following the steps outlined:

1. CD + DE = EF + DE by the (addition) Property of Equality.

This shows that the same value has been added to both sides of the equation.

2. CE = CD + DE and DF = EF + DE through (segment addition).

This indicates that CE and DF are segments, and the length of any segment equals the total of its parts.

3. CE = DF according to the (Addition, subtraction, substitution, transitive) Property of Equality. Recognizing that CE = CD + DE and using the fact that CD = EF allows us to replace CD with EF.

So, CE = EF + ED = FD (via substitution) Property of Equality.

4. Since AB = CE and CE = DF, we can conclude AB = DF by the (transitive) Property of Equality.

This follows the rule that if x = y and y = z, then x = z.

We start with the following information:

p = probability = 0.12<span>
n = total number of students = 39 </span>

x = number of left-handers = 5<span>
u = mean = p * n = 4.68
σ = standard deviation = √(n*p*(1-p)) = √(39 * 0.12 * 0.88) = 2.03</span>

Finding the z score:

z = (x – u) / σ

<span> z = (5 – 4.68) / 2.03
</span>

z = 0.1576 = 0.16

<span>

</span>Applying standard tables for z gives the p value as:

p value = 0.5636 = 56.36%

 

Consequently, there is a 56.36% probability.