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oee
6 days ago
9

a jewelry is designing a crown. the crown must have at least 45 gems using only emeralds, rubies, and diamonds. the number of ru

bies must be 1 less than 3 times the number of emeralds. the number of diamonds must be 4 or less than the number of rubies. which inequality could the jewelry maker use to find the number of emeralds, x, that can be placed on the crown>
Mathematics
1 answer:
Inessa [11.2K]6 days ago
5 0
I'm quite terrible at this aspect, so I'm merely making a guess.
X serves as the variable while x denotes the multiplication symbol.
X + (X x 3 - 1) + (X x 3 - 1) - 4) <span>≥ 45 is the outcome I arrived at.
The solution to that inequality is
X </span><span>≥ 7, I suppose.</span>
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The warehouse already has 27 pallets of stock waiting to be unloaded, and the delivery van arrives with another 8. The warehouse
PIT_PIT [11116]
To find the solution, you need to add 27 and 8 together, which results in 35. After calculating that, you should subtract 32 from 35, leading to a remainder of 3, indicating that 3 extra pallets will be remaining as your answer.
5 0
28 days ago
Write 1.653 x 10-4 as an ordinary number.​
zzz [11029]

Answer:

1.4×10⁻⁵=0.000014

Step-by-step explanation:

Since the exponent of the 10 term is negative, shift the decimal point to the left by 5 positions;

1.4×10⁻⁵=0.000014

3 0
16 days ago
for the level 3 course, examination hours cost twice as much as workshop hours and workshop hours cost twice as much as lecture
Leona [11201]

Answer:

The hourly rate for lectures is $7.33

Step-by-step explanation:

* Let's break down how to tackle the problem.

- For the level 3 course, examination hours are priced at double that of workshop hours.

- Workshop hours cost twice the rate of lecture hours.

- The total includes examination, workshop, and lecture hours.

- Examination lasts 3 hours, workshops 24 hours, and lectures 12 hours.

* Let’s denote the cost of lecture hours as $x per hour.

∴ The lectures cost $x per hour.

∵ Workshop charge is twice that of lectures

∴ Workshop hours cost 2(x) = 2x per hour.

∵ Examination fees are double that of workshop hours

∵ The workshop cost is 2x

∴ Examination fees are 2(2x) = 4x per hour.

- Combining costs for level 3 gives us the total of lecture, workshop, and examination hours.

∵ 12 hours for lectures

∵ 24 hours for workshops

∵ 3 hours for examinations

∵ Thus the total cost for level 3 = 12(x) + 24(2x) + 3(4x).

∴ Total cost for level 3 = 12x + 48x + 12x.

∵ Therefore, total cost = $528.

∴ 12x + 48x + 12x = 528.

∴ 72x = 528; hence we divide both sides by 72.

∴ x = 7.33.

∵ x represents the cost of lecture hours per hour.

∴ Therefore, the hourly price for lectures is $7.33.

6 0
1 month ago
Need help on 4.9.2 project: performance task: the subway stop
tester [10823]
You might have better success by searching for answers individually:)
3 0
1 month ago
We can calculate EE, the amount of euros that has the same value as DD U.S. dollars, using the equation E=\dfrac{17}{20}DE=
Leona [11201]

Response:

The equation provided is e=\frac{17}{20}d, where e represents euros and d denotes the equivalent value in U.S. Dollars.


We aim to determine the number of euros for 1 U.S. Dollar.


Substituting d=1 in the above equation


results in


e=\frac{17}{20}(1)


Simplifying gives us


e=\frac{17}{20}


By dividing 17 by 20, we get 0.85.


Thus, 0.85 euros are equivalent to 1 U.S. Dollar.


Read more on -

Step-by-step explanation:


5 0
17 days ago
Read 2 more answers
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