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Ira Lisetskai
13 days ago
9

Which of the following sets of materials is required by both eukaryotes and prokaryotes for replication? Group of answer choices

Biology
1 answer:
s2008m [1.6K]13 days ago
6 0

Response:

Double-stranded DNA.

Clarification:

Replication refers to the process of creating daughter DNA from parent DNA with assistance from enzymes and proteins. The replication process comprises three main phases: initiation, elongation, and termination.

The double-stranded DNA molecule undergoes replication, requiring four distinct dNTPs - adenine, guanine, thymine, and cytosine. Primers are necessary to start the replication process, and the ori region serves as the initiation site.

Consequently, the correct answer is option (a).

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Which of the following is NOT a component of the cell membrane? * 1 point (a) Phospholipids (b) Sterols (c) Proteins (d) Nucleic
enyata [1788]

Answer:

d

Explanation:

Nucleic acid is found within the nucleus.

It is not associated with the cell membrane.

3 0
27 days ago
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Lipogenesis is common for organic molecules because the intermediate ________ is formed in most nutrient metabolic processes. gl
vlada-n [1829]
I believe Lipogenesis is prevalent in organic molecules because the intermediate Acetyl-CoA is involved in most metabolic pathways. Lipogenesis entails synthesizing fatty acids from Acetyl-CoA. Acetyl-CoA plays an intermediate role in the metabolism of simple sugars like glucose, which serves as the primary energy source for many living organisms.  
6 0
5 days ago
What would be direct consequences from decreasing angiosperm biodiversity? Select all that apply. extinction of animals balancin
vlada-n [1829]

Answer:

reduction in potential medicines

decreased food supply

Explanation:

The direct impacts of a decline in angiosperm biodiversity include a decrease in accessible medicines and food sources.

Angiosperm biodiversity, or flowering plants, serve as essential food sources for numerous living organisms, including humans, clearly demonstrated in human agricultural practices. Various consumer categories within ecosystems rely heavily on flowering plants for sustenance, whether directly or indirectly.

Moreover, they also provide medicinal resources. For instance, chloroquine, a principal treatment for malaria, is derived from the flowering plant Chinchona pubescens.

Many species of flowering plants remain uncatalogued in the wild, holding potential for future food and medicinal applications.

Therefore, a loss in flowering plant diversity will directly lead to a reduction in available food and medicine.

3 0
22 days ago
A segment of DNA produces methionine, threonine, histidine, aspartate, and glycine when translated. A substitution mutation occu
garik1379 [1541]

Answer:

AUGUCCCACGAUGGGUGA

Methionine- Serine- Histidine- Aspartate- Glycine- Stop

Explanation:

During the process of gene expression, DNA, which contains genetic information, is transcribed into mRNA, and this mRNA is then translated into a sequence of amino acids. This transcription abides by the rules of complementary base pairing, translating as A-U, G-C, and T-A.

In mRNA, nucleotide sequences are organized into sets of three bases known as CODONS. Each of these codons corresponds to a specific amino acid.

In this scenario, a piece of DNA encodes methionine, serine, histidine, aspartate, and glycine after translation. However, a mutation leads to the sequencing shown: 3' – TACAGGGTGCTACCCACT – 5'.

The mutated DNA's corresponding mRNA sequence would be: AUGUCCCACGAUGGGUGA

Throughout translation, these codons yield the following amino acids:

AUG - methionine

UCC - Serine

CAC - Histidine

GAU - Aspartate

GGG - Glycine

UGA - Stop codon

Therefore, the resultant peptide chain from the revised DNA sequence will be: Methionine- Serine- Histidine- Aspartate- Glycine- Stop

3 0
21 day ago
A planet has an average distance to the sun of 4.54 AU. In two or more complete sentences, explain how to calculate the orbital
lana [1794]
By applying Kepler's third law of planetary motion, we understand that the square of the orbital period corresponds to the cube of the semi-major axis. Given that Earth orbits at 1 AU with a 1-year period, we can establish the ratio:
P^2 / r^3= 1
(P)^2 = 4^3
<span>P = 4^(3/2) = 8 years </span>
8 0
22 days ago
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