Jeremiah is correct. Division by 0 is undefined, and no number can be evenly divided by 0.
Ensure you represent the powers accurately. While I understand your point, others might not. Therefore, it's step 2. The 4 serves as an exponent, not as an addition.
Answer:
6 knots
Step-by-step explanation:
Let the velocity be v knots
thus, the time required to traverse 500 M is given by 500 / v hours
Fuel consumption per hour is equal to 216 plus half the cube of the speed (v^3).
Let F denote the fuel consumption for the journey
= [500/v][216 + 0.5v^3]
= 500[216/v + 0.5v^2]
The derivative of F with respect to v is: dF/dv = 500[ - 216/v^2 + v]
The second derivative, d^2F/d^2v = 500[432/v^3 + 1], indicates positivity.
Setting dF/dv to zero helps find the minimum.
500[ -216/v^2 + v] = 0
or v = 216/v^2
or v^3 = 216
By solving, we arrive at v = [216]^(1/3) = 6 knots
Answer:
a. 80 students
b. 92 students
Step-by-step explanation:
Designate arts students as A and dance students as D.
Thus, we have,[['[TAG_14]]
n(A) = 35
n(D) = 57
Required
To determine n(A or D)
For (a):
We find that:
n(A and D) = 12
The calculation for n(A or D) is as follows:
n(A or D) = n(A) + n(D) - n(A and D)
n(A or D) = 35 + 57 - 12
n(A or D) = 80
b. Given the details
n(A and D) = 0 since no students are enrolled in both classes as indicated in (a)
Using the same formula as in (a).
n(A or D) = n(A) + n(D) - n(A and D)
n(A or D) = 35 + 57 - 0
n(A or D) = 92
2000
1 caja = 1400/7 = 200
200×3=600
1400+600=2000
Explicación paso a paso:
Dado: Los trabajadores han empaquetado 1,400 vasos en 7 cajas.
A buscar: Si empacan 3 cajas más, ¿cuántos vasos habrán empaquetado en total?
Solución:
Vasos empaquetados en 7 cajas = 1400
Vasos en 1 caja =
Vasos en 3 cajas =
Por lo tanto, al inicio empacaron 1400 vasos.
Si empacan 3 cajas más, agregarán 600 vasos adicionales.
Por lo tanto, el número total de vasos empaquetados por los trabajadores = 1400+600 = 2000
Así que han empaquetado 2000 vasos en total.
