Response: Yes, it is
Detailed explanation:
Since the average scores of both sets of students vary, evaluating the mean score in relation to their class will clarify which class supports or contradicts the professor's research
Step-by-step explanation:
I included the work done
James will retain his original t toy cars along with half of (t+13) cars, resulting in a total of...
... t + (t + 13/2) = (3t + 13)/2.... cars after receiving a gift from Paul.
Pr(X>1540.2) = 0.0655. Step-by-step explanation: The expected value indicated for the large bottle is E(Large) = 1016, and for the small bottle, E(small) = 510. This leads to an expected total E(total) = 1016 + 510 = 1526. The new mean calculated is thus 1526. To find the standard deviation, we derive the variance of each bottle. The variance for the large bottle is v(large) = 8^2 = 64, while for the small bottle it's v(small) = 5^2 = 25. Hence, the total variance is v(total) = 64+25 = 89, resulting in a new standard deviation sd(new) = sqrt(89) = 9.434. To find the probability, we compute using the new mean and standard deviation. The z score is derived as z = (x - mean)/sd = (1540.2 - 1526)/9.434 = 1.505. Looking up this z score gives P(z<1.51) = 0.9345. Consequently, for x > 1540.2, we have P(z > 1.51) = 1 - 0.9345 = 0.0655.
Multiply 0.001 by 26 to arrive at the answer of 0.026.