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Svetach
3 months ago
10

Which of the following describes the graph of y = StartRoot negative 4 x minus 36 EndRoot compared to the parent square root fun

ction?
stretched by a factor of 2, reflected over the x-axis, and translated 9 units right
stretched by a factor of 2, reflected over the x-axis, and translated 9 units left
stretched by a factor of 2, reflected over the y-axis, and translated 9 units right
stretched by a factor of 2, reflected over the y-axis, and translated 9 units left
Mathematics
2 answers:
zzz [12.3K]3 months ago
8 0

Answer:

stretched by a factor of 2, reflected over the y-axis, and translated 9 units left

Step-by-step explanation:

babunello [11.8K]3 months ago
3 0

Answer:

stretched by a factor of 2, reflected over the y-axis, and translated 9 units left

Step-by-step explanation:

The provided function is y=\sqrt{-4x-36}

We can reformulate this function by factoring out -4 in the radicand, resulting in:

y=\sqrt{-4(x+9)}

Next, we simplify the square root of 4:

y=2\sqrt{-(x+9)

The parent function is y=\sqrt{x}

By comparing it to the parent function, we discern that there is a stretch by a factor of 2, a reflection across the y-axis, and a translation 9 units to the left.

The last option is accurate.

You might be interested in
In right triangle qrs, angle r is a right angle. The altitude rt is drawn to hypotenuse qs. If qr is 20 and qs is 25 then find t
lawyer [12517]

Answer:

qt's length = 16

Step-by-step explanation:

The problem states that qrs is a right triangle,

where qr = 20

          sr =?

          qs = 25

          qt =?

1)

Calculate sr

hypotenuse² = base² + height²

sq² = sr² + rq²

25² - 20² = sr²

sr = √(25² - 20²)

sr = 15

2)

When altitude rt is dropped to hypotenuse qs, it creates

two right triangles: rtq and rts.

Δrtq

height = rt

base= tq = 25 - x

hypotenuse = qt = 20

Δrts

height = rt

base= ts = x

hypotenuse = sr = 15

Both triangles share the same height, which is rt

Using the Pythagorean theorem:

      Δ rtq                                           Δ rts

hypotenuse² - base² = height²

20² - (25 - x)² = 15² - x²

400 - (625 + x² - 50x) = 225 - x²

400 - 625 - x² + 50x = 225 - x²

-225 - x² + 50x - 225 + x² = 0

-450 + 50 x = 0

50x = 450

x = 450/50

x = 9

Base of Δ rtq = tq = 25 - x

                         tq = 25 - 9

                         tq = 16  

5 0
3 months ago
Read 2 more answers
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