Which of the following describes the graph of y = StartRoot negative 4 x minus 36 EndRoot compared to the parent square root fun

The likelihood of observing a sample mean that is less than 18 hours is 0.0082. \nTo evaluate this probability, we calculate the z-score for a sample mean of 18. Accordingly, the probability of getting a sample mean below 18 hours becomes P(z<z(18)). \nThe z-score is calculated as follows: \nz(18) = [(X - M) / s] where: \n- X is the sample mean (18 hours) \n- M is the average hours dentists devote weekly to fillings (20 hours) \n- s is the standard deviation (10 hours) \n- N is the sample size (144) \nSubstituting the numbers leads to: \nz(18) = [(18 - 20) / (10/sqrt(144))]. Using the z-table, we find that P(z<z(18)) is 0.0082.

Answer:

A) The estimated proportion of women whose platelet counts fall within 2 standard deviations of the mean, or between 118.5 and 377.3, is 95%.

B) The estimated percentage of women with platelet counts ranging from 53.8 to 442.0 is 99.7%.

Step-by-step explanation:

Provided data:

mean;μ = 247.9

standard deviation;σ = 64.7

A) We seek to find the estimated percentage of women with platelet counts within 2 standard deviations from the mean, which translates to values between 118.5 and 377.3.

Based on the attached image, the empirical curve indicates that the likelihood within 1 standard deviation of the mean is (34% + 34%) = 68%.

In contrast, the likelihood within 2 standard deviations from the mean is (13.5% + 34% + 34% + 13.5%) = 95%

Therefore, the estimated percentage of women having platelet counts within 2 standard deviations of the mean, or ranging from 118.5 to 377.3, equals 95%

B) Next, we want to determine the estimated percentage of women with platelet counts between 53.8 and 442.0.

The values of 53.8 and 442.0 correspond to 3 standard deviations from the mean.

Let’s verify that.

Since mean;μ = 247.9

standard deviation;σ = 64.7;

μ = 247.9

σ = 64.7

μ + 3σ = 247.9 + 3(64.7) = 442

Also;

μ - 3σ = 247.9 - 3(64.7) = 53.8

From the attached empirical curve, it can be seen that at 3 standard deviations from the mean, the probability percentage is;

(2.35% + 13.5% + 34% + 34% + 13.5% + 2.35%) = 99.7%

The probability is 0. Fair dice have six sides, and each side has an equal chance of being rolled. The maximum possible outcome with two dice is 6 + 6 = 12, rendering a total of 13 unattainable. Hence, the probability of achieving a total of 13 is 0.

Sam needs to score 97 on his upcoming test to keep his average at 85. If you total 63, 84, 96, and 97, the sum is 340. Dividing 340 by four test scores yields an exact average of 85.

Answer:

Explanation:

Hello!

You possess a sample involving 200 participants, who were surveyed regarding their main source of news, categorized into (1) Television, (2) Radio, (3) Internet, and (4) Other.

Your goal is to evaluate whether the proportions in this sample align with the established frequencies of 10%, 30%, 50%, and 10% respectively.

The suitable statistical method to assess if the sample matches the known or historical distribution is the Chi-Square goodness of fit test. In this test, the null hypothesis represents the model or distribution under examination. In this scenario, you need to articulate the proportions for each category:

H₀: P(1)= 0.10; P(2)= 0.30; P(3)= 0.50; P(4)= 0.10

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