In the absence of a specific question posed, below are the potential inquiries along with their respective answers:
P(fewer than 4 tosses)
= P(one toss) + P(two tosses) + P(three tosses)
= (3/4) + (3/4)(1/4) + (3/4)(1/4)^2
= 0.984375
Expected value
= 1 / p
= 1 / (3/4)
= 4 / 3
Variance
= (1 - p) / p^2
= (1 - (3/4)) / (3/4)^2
= (1/4) / (9/16)
= 4 / 9
Standard deviation
= sqrt(Variance)
= sqrt(4 / 9)
= 2 / 3
Answer:
Step-by-step explanation:
It has been established that the count of drivers traveling between a specific origin and destination in a certain time frame follows a Poisson distribution with a mean μ = 20 (as indicated in the article "Dynamic Ride Sharing: Theory and Practice"†).
a) 
b) 
c) 
d) 2 standard deviations = 2(20) = 40
Thus, this means the range for 2 standard deviations is
20-40, 20+40
which equates to (0,60)
Based on the provided information about the metals' melting point, boiling point, and density, the response is A. The gold sample transitions from liquid to gas at the highest temperature, while the copper sample occupies the most volume. Gold's boiling point is the highest at 2660, and copper has the lowest density, which correlates with a larger volume since density is defined as mass divided by volume.
1 cg equals 10^-5 kg
Thus, 8.25 * 10^2 cg converts to 8.25 * 10^-3 kg
1 nanogram is represented as 10^-12 kg
Consequently, 8.25 * 10^-3 kg is equivalent to 8.25 * 10^9 nanograms
As a result, 8.25 * 10^2 cg is equal to 8.25 * 10^9 nanograms.
